在UNIX中查找和删除 [英] Find and remove in unix

问题描述

下面是我的输入文件:

sample.txt:

3"
6-position
7' 4" to 10' 3-1/2"
4.8"
Adjustable from 99" to 111" - max 148

，在输出中，我只需要3，即

and in the output I only need 3, i.e.

output.txt:

3
4.8

所以基本上我需要打印"符号的数字值，其他非数字文本需要完全删除.

So basically I need to print the numeric value for the " symbol, other non-numeric text needs to be removed entirely.

我试图用sed来实现这一点，但是我无法获得期望的结果.

I tried to implement this with sed, but I was not able to get the desired result.

有什么方法可以在UNIX上实现这一目标吗?

Is there any way to achieve this on UNIX?

推荐答案

awk更适合执行此类任务:

awk is more suited to perform this type of task:

awk '/^ *[0-9]*(\.[0-9]+)?" *$/{sub(/"/, ""); print}' inFile

输出:

3
4.8

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