如何在自己的流程组中启动流程? [英] How to start a process in its own process group?

问题描述

我想在其自己的进程组中启动一个进程(或者，一旦启动，则更改其组)，并且:

I would like to start a process in its own process group (or, alternatively, change its group once started) and:

• 让该组中的进程从终端响应Ctrl + C
• 获取进程组的ID，以便我可以通过kill命令终止该组中的所有进程.

• have the processes in the group respond to Ctrl + C from the terminal
• get the id of the process group so that I can terminate all the processes in the group via the kill command.

注意:我尝试了setsid prog [args]，但是进程没有从终端响应Ctrl + C，也无法获得新的进程组ID.

Note: I tried setsid prog [args] but the processes do not respond to Ctrl+C from the terminal nor I could get the new process group id.

我还尝试通过Perl的setpgrp($pid, $pid)和POSIX::setpgid($pid, $pid)更改进程组，但无济于事.

I also tried to change the process group via Perl's setpgrp($pid, $pid) and POSIX::setpgid($pid, $pid), to no avail.

更大的问题:

我有一个进程(单线程；我们称它为多产"进程P)，该进程同步启动一个子进程(一个接一个；当前一个子进程终止时，它启动一个新的进程).从终端，我希望能够杀死P及其下面的进程树.为此，我可以简单地安排杀死P组中的进程.但是，默认行为是P在其父进程的组中.这意味着，如果我杀死P组中的所有进程，则P的父级将被杀死，除非我将P及其树放在自己的组中.

I have a process (single-threaded; let's call it the "prolific" process P) that starts many child processes synchronously (one after another; it starts a new one when the previous child process terminates). From the terminal, I want to be able to kill P and the tree of processes below it. To do that, I could simply arrange to kill the processes in P's group. However, the default behavior is that P is in the group of its parent process. That means that P's parent will be killed if I kill all the processes in P's group, unless I have P and its tree be in their own group.

我的意图是杀死P及其下面的树，而不是P的父级.另外，我无法修改P的代码本身.

My intention is to kill P and the tree below it, but not P's parent. Also, I cannot modify P's code itself.

推荐答案

在自己的进程组中启动进程"是什么意思? Shell在自己的进程组中启动进程，这就是它进行工作控制的方式(通过在前台有一个进程组，在后台启动的每个管道都有几个进程组).

What do you mean "start a process in its own process group"? The shell launches processes in their own process groups, that's how it does job control (by having a process group for processes in the foreground, and several process groups for every pipeline launched on the background).

要查看shell为每个管道启动一个新的进程组，可以执行以下操作:

To see that the shell launches a new process group for every pipeline, you can do this:

ps fax -o pid,pgid,cmd | less

它将显示如下内容:

11816 11816  |   \_ /bin/bash
4759   4759  |       \_ ps fax -o pid,pgid,cmd
4760   4759  |       \_ less

请注意，shell为管道创建了一个新的进程组，并且管道中的每个进程都共享该进程组.

Note that the shell has created a new process group for the pipeline, and every process in the pipeline shares the process group.

我想我知道你在做什么.您正在从Perl调用system.显然，sh -c不会创建新的进程组，因为它是一个没有作业控制的外壳.

I think I know what you are getting at. You are calling system from Perl. Apparently, sh -c doesn't create new process groups, since it's a shell without job control.

我要做的是先fork，然后在孩子身上:

What I would do would be to fork, then on the child:

setpgrp;
system("ps fax -o pid,pgid,cmd");

和wait在父级上.

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