Linux:如何消除睡眠 [英] Linux: How to kill Sleep

问题描述

更多的概念性问题.如果我编写的bash脚本执行类似

More of a conceptual question. If I write a bash script that does something like

control_c()
{
echo goodbye
exit #$
}

trap control_c SIGINT

while true
do
sleep 10 #user wants to kill process here.
done

当睡眠10运行时，

control + c不会退出.是因为linux sleep忽略了SIGINT吗?有没有办法避免这种情况并使用户能够在睡眠状态下退出cntrl + c?

control+c won't exit when sleep 10 is running. Is it because linux sleep ignores SIGINT? Is there a way to circumvent this and have the user be able to cntrl+c out of a sleep?

推荐答案

您所描述的内容与仅发送给bash脚本而不是进程组的中断信号是一致的.您的脚本会收到信号，但sleep不会，因此您的陷阱要等到sleep完成后才能执行.标准技巧是在后台运行sleep并在其上运行wait，以便wait接收中断信号.然后，您还应该将SIGINT明确发送给仍在运行的任何子进程，以确保它们退出.

What you are describing is consistent with the interrupt signal going to only your bash script, not the process group. Your script gets the signal, but sleep does not, so your trap cannot execute until after sleep completes. The standard trick is to run sleep in the background and wait on it, so that wait receives the interrupt signal. You should also then explicitly send SIGINT to any child processes still running, to ensure they exit.

control_c()
{
echo goodbye
kill -SIGINT $(jobs -p)
exit #$
}

trap control_c SIGINT

while true
do
sleep 10 &
wait
done

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