安卓：java.lang.IllegalStateException：指定的小孩已经有一个父。您必须先对孩子的父母打电话removeView（）。 [英] Android: java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.

问题描述

我mking中，我想提出动态表行一个Android应用程序，然后动态地添加imageviews和textviews它。
它增加了第一排，然后给下面的异常

I am mking an android app in which i am making dynamically table rows and then adding imageviews and textviews to it dynamically. It adds the first row and then give the following exception

java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.

我用下面的code吧：

I am using the following code for it:

          ar1= new JSONArray(children.toString());
                                for(int mn=0;mn<ar1.length();mn++){
                                    value=ar1.getString(mn);
    TableRow tr = new TableRow(HomePageWithPhoneIsOfflineDialog.this);
                                    tr.setBackgroundColor(Color.WHITE);
                                    tr.setId(100+mn);
                                    tr.setMinimumHeight(60);
                                    tr.setLayoutParams(new LayoutParams( LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));
                                    TextView child= new TextView(HomePageWithPhoneIsOfflineDialog.this);
                                    child.setId(200+mn);
                                    child.setHeight(50);
                                    child.setGravity(Gravity.CENTER);
                                    child.setTextColor(Color.BLACK);
                                    System.out.println(value);
                                    child.setText(value);
                                    System.out.println("adding iv");
                                    tr.addView(iv,0);
                                    System.out.println("adding child");
                                    tr.addView(child);
                                    System.out.println("adding table row");
                                     table.addView(tr, new TableLayout.LayoutParams(LayoutParams.FILL_PARENT,LayoutParams.WRAP_CONTENT));

}

谁能告诉我怎么解决这个问题。

Can anyone tell me how to solve this problem.

感谢

推荐答案

时，没有循环，所以我想象的是之前创建中创建的四变量要添加，......但在第二循环中它添加两个不同的表行。

The iv variable that you are adding, is not been created inside the loop so I imagine is created before... but in the second loop it's added to two different Table Rows.

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