如何在JSP页面中获取Eclipse项目的路径 [英] How to get the path of an eclipse project in jsp page

查看:163
本文介绍了如何在JSP页面中获取Eclipse项目的路径的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如何获取当前项目的路径:这是一个使用maven原型创建的动态Web应用程序.

How to get the path of my current project : it's a dynamic web application created with maven archetype .

我想用scriptlet代码在jsp页面中检索路径,我使用了不同的代码,但是我总是会获取eclipse的路径(C:\ Users \ Amira \ Desktop \ eclipse \ eclipse) 或tomcat上的Web应用程序的路径((C:\ software \ apache-tomcat-7.0.28 \ apache-tomcat-7.0.28 \ wtpwebapps \ TestProjectUI)

I want to retrieve the path in my jsp page in scriptlet code , i used different codes but i'm always getting the path of eclipse (C:\Users\Amira\Desktop\eclipse\eclipse) or the path of the web application on tomcat ((C:\software\apache-tomcat-7.0.28\apache-tomcat-7.0.28\wtpwebapps\TestProjectUI)

但是我想要项目在我的工作空间中的路径:C:\ Users \ Amira \ junoWorkspace \ TestProjectUI

but i want the path of the project in my workspace : C:\Users\Amira\junoWorkspace\TestProjectUI

任何想法都会受到赞赏 谢谢

Any idea will be appreciated Thank you

这是我的jsp:

<body>

<%
if (request.getParameter("btnSubmit") != null) //btnSubmit is the name of your button,not id of that button.
{

    String className = request.getParameter("testclass");
    System.out.println(className);
    String[] command = {"CMD", "/C", "mvn -Dtest=" + className + " test"};
    ProcessBuilder probuilder = new ProcessBuilder(command);

    //You can set up your work directory
    probuilder.directory(new File("C:\\Users\\Amira\\junoWorkspace\\TestProjectUI"));

    Process process = probuilder.start();

    //Read out dir output
    java.io.InputStream is = process.getInputStream();
    InputStreamReader isr = new InputStreamReader(is);
    BufferedReader br = new BufferedReader(isr);
    String line;
    System.out.printf("Output of running %s is:\n", Arrays.toString(command));
    while ((line = br.readLine()) != null) {
        System.out.println(line);
    }

    //Wait to get exit value
    try {
        int exitValue = process.waitFor();
        System.out.println("\n\nExit Value is " + exitValue);
    } catch (InterruptedException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}
%>

        <html:file properties="tonFichier" name="tonForm"/>


        <p>   Please specify a Test :<br>
            <input type="file" name="testclass" size="40" >
        </p>
        <div>
            <input type="submit" id="btnSubmit" name="btnSubmit" value="Execute Test"/>

        </div>
    </form>
</body>

推荐答案

每当遇到此类问题时,我都会打印出所有System.getProperties(),并查看是否有我想要的信息.这可能是您在此处可以做的最好的事情,因为Eclipse提供的唯一信息将通过一个属性来提供.如果您提供的属性之一中没有信息,则可以将其作为启动配置的一部分自己提供,可以在启动配置中使用workspace_loc变量.

Whenever I have a problem like this, I print out all of the System.getProperties() and see if there is one that has the information I want. This is probably the best you can do here, since the only information provided by Eclipse will come through a property. If you don't have the information in one of the provided properties, you can provide it yourself as part of your launch configuration, you can use the workspace_loc variable in the launch config stuff.

这篇关于如何在JSP页面中获取Eclipse项目的路径的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆