矩阵的平均行 [英] Mean Row of Matrix

问题描述

我正在尝试使用mean(A,1)来获取矩阵A的均值行，但出现错误.

I'm trying to use mean(A,1) to get the mean row of a matrix A, but am getting an error.

例如，尝试运行命令mean(eye(3), 1).
这给出了错误no method mean(Array{Float64,2},Int32).

For example, try running the command mean(eye(3), 1).
This gives the error no method mean(Array{Float64,2},Int32).

我可以找到有关mean函数的唯一文档:
http://docs.julialang.org/en/release-0.1 /stdlib/base/#statistics

The only documentation I can find for the mean function is here:
http://docs.julialang.org/en/release-0.1/stdlib/base/#statistics

mean(v[, region])

计算整个数组v的均值，或者可选地沿region中的维计算.

Compute the mean of whole array v, or optionally along the dimensions in region.

什么是region参数?

编辑:对于Julia 0.7及更高版本，请将其写为mean(v, dims=1).

EDIT: for Julia 0.7 and higher, write this as mean(v, dims=1).

推荐答案

必须与您的安装有关，mean(eye(3),1)在这里可以正常工作.

It must be something with your installation, mean(eye(3),1) works just fine here.

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