朱莉娅实时绘图 [英] real time plotting with Julia

问题描述

我正在尝试绘制一个随Julia实时变化的函数.

I am trying to plot a function evolving in real time with Julia.

为此，当我尝试完全使用给出的示例

For that, I saw that GR package could be used in Julia, when I try to apply exactly the example given here :

import GR
GR.inline("mov")
x = [0:0.01:2*pi]

    for i = 1:200
    GR.plot(x, sin.(x + i / 10.0))
    end

GR.show()

执行循环部分时收到以下错误消息:

I get the following error message while executing the loop part :

预期实数或复数

/myname/.julia/v0.5/GR/src/jlgr.jl:936 ....

我在互联网上看了一下，发现这类似的问题，但是我真的不明白答案，应该怎么做才能使它起作用.

I have looked a bit on internet and found this where someone seems to have a similar problem but I really dont understand the answers and what should I do to make it work.

我还可以找到另一种实时绘制图形的方式(循环内).

I can also just find an other way to plot in real time (within a loop).

有人可以帮忙吗?

先谢谢您

推荐答案

这里是一种使用图"绘制到GR的解决方案.我确信这也可以直接在GR中完成，但不确定您的示例出了什么问题.

Here is a solution that uses Plots to plot to GR. I am sure this can be done in GR directly as well, but not sure what is wrong with your example.

using Plots
gr(show = true) # in IJulia this would be: gr(show = :ijulia)
x = 0:0.01:2*pi
for i in 1:200 
    display(plot(x, sin.(x + i / 10.0)))
end

请注意，此示例是实时的(根据问题)，因此可能会有些滞后.在示例代码中，创建了一个gif，然后将其显示给ijulia.

Note that this example is real-time (as per the question) and thus may lag a little. In the code in the example, a gif is created instead, which is then displayed to ijulia.

这篇关于朱莉娅实时绘图的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！