是否可以在不使用powermock的情况下在Mockito中模拟UUID? [英] Is there away to mock UUID in Mockito without using powermock?

问题描述

我想模拟一个具有uuid值的对象，但是我不想安装powermock.

I want to mock an object that has a uuid value but I don't want to install powermock.

推荐答案

您最简单的方法是包装UUID生成.

Your easiest way to achieve this will be to wrap up your UUID generation.

假设您有一个使用UUID.randomUUID

public Clazz MyClazz{

public void doSomething(){
    UUID uuid = UUID.randomUUID();
}

}

UUID源代码完全与JDK实现联系在一起.一种解决方案是包装UUID生成，可以在测试时用不同的依赖项替换它.

The UUID geneartion is completely tied to the JDK implementation. A solution would to be wrap the UUID generation that could be replaced at test time with a different dependency.

Spring具有针对此确切参数的接口，

Spring has an interface for this exact senario, https://docs.spring.io/spring/docs/current/javadoc-api/org/springframework/util/IdGenerator.html

我不建议您仅出于参考目的将Spring用于此界面.

I'm not suggesting you use Spring for this interface just informational purposes.

然后您可以打包UUID代，

You can then wrap up your UUID generation,

public class MyClazz{

private final idGeneartor;

public MyClazz(IdGeneartor idGenerator){
    this.idGenerator = idGenerator;
}

public void doSomething(){
    UUID uuid =idGenerator.generateId();
}

然后，您可以根据自己的需要实现UUID创世记的多种实现方式

You can then have multiple implementations of UUID geneartion depending on your needs

public JDKIdGeneartor implements IdGenerator(){

    public UUID generateId(){
       return UUID.randomUUID();
    }
}

还有一个硬编码的impl，它将始终返回相同的UUID.

And a hardcoded impl that will always return the same UUID.

public HardCodedIdGenerator implements IdGenerator(){

    public UUID generateId(){
       return UUID.nameUUIDFromBytes("hardcoded".getBytes());
    }
}

在测试时，您可以使用HardCodedIdGeneartor构造对象，让您知道生成的ID是什么并更自由地断言.

At test time you can construct your object with the HardCodedIdGeneartor allowing you to know what the generated ID will be and assert more freely.

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