Jython(JES)-90度旋转功能 [英] Jython (JES) - 90 degree rotation function

问题描述

我需要编写一个函数spin(pic，x)，它将在其中拍摄图片并将其逆时针X倍旋转90度.我在函数中只有顺时针旋转90度:

I need to write a function spin(pic,x) where it will take a picture and rotate it 90 degrees counter clockwise X amount of times. I have just the 90 degree clockwise rotation in a function:

def rotate(pic):
    width = getWidth(pic)
    height = getHeight(pic)
    new = makeEmptyPicture(height,width)
    tarX = 0
    for x in range(0,width):
        tarY = 0
        for y in range(0,height):
            p = getPixel(pic,x,y)
            color = getColor(p)
            setColor(getPixel(new,tarY,width-tarX-1),color)
            tarY = tarY + 1
        tarX = tarX +1
    show(new)
    return new

..但是我不知道如何编写一个将其旋转X次的函数.有人知道我该怎么做吗?

.. but I have no idea how I would go about writing a function on rotating it X amount of times. Anyone know how I can do this?

推荐答案

您可以拨打rotate() X次:

def spin(pic, x):
    new_pic = duplicatePicture(pic)
    for i in range(x):
         new_pic = rotate(new_pic)
    return new_pic


a_file = pickAFile()
a_pic = makePicture(a_file)
show(spin(a_pic, 3))

但这显然不是最优化的方法，因为您将计算X图像而不是您感兴趣的图像.我建议您首先尝试一种基本的switch...case方法(即使该语句在Python中不存在) ;):

But this is clearly not the most optimized way because you'll compute X images instead of the one you are interested in. I suggest you try a basic switch...case approach first (even if this statement doesn't exists in Python ;):

xx = (x % 4)     # Just in case you want (x=7) to rotate 3 times...

if (xx == 1):
    new = makeEmptyPicture(height,width)
    tarX = 0
    for x in range(0,width):
        tarY = 0
        for y in range(0,height):
            p = getPixel(pic,x,y)
            color = getColor(p)
            setColor(getPixel(new,tarY,width-tarX-1),color)
            tarY = tarY + 1
        tarX = tarX +1
    return new
elif (xx == 2):
    new = makeEmptyPicture(height,width)
    # Do it yourself...
    return new
elif (xx == 3):
    new = makeEmptyPicture(height,width)
    # Do it yourself...
    return new
else:
    return pic

然后，也许您将能够看到一种将这些案例合并为单个(但更为复杂)的方法.double for loop ...玩得开心...

Then, may be you'll be able to see a way to merge those cases into a single (but more complicated) double for loop... Have fun...

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