无法根据需要转义网址 [英] Cannot escape url as needed

问题描述

我想逃避路径中的某些值.

I am tring to escape some values in a path.

假设我正在尝试获取https://www.google.com/https%3A%2F%2Fdomain

我尝试了以下选项:

Scenario: escape value
    * url "https://www.google.com"
    * path "https://domain"
    When method get
    * path "https\:\/\/domain"
    When method get
    * path "https%3A%2F%2Fdomain"
    When method get
    * path "https\\:\\/\\/domain"
    When method get

但是我得到

1. https://www.google.com/https://domain
2. https://www.google.com/https://domain
3. https://www.google.com/https%253A%252F%252Fdomain

1. https://www.google.com/https://domain
2. https://www.google.com/https://domain
3. https://www.google.com/https%253A%252F%252Fdomain

为什么%2F被转义到%252F时为什么\不起作用?

Why is \ not working, while %2F is being escaped into %252F?

推荐答案

编码是正确的行为: https://www.w3schools.com/tags/ref_urlencode.asp

但是您可以在空手道中找到此异常URL的解决方法，使其成为url本身的一部分:

But your workaround for this un-usual URL is in Karate make it as part of the url itself:

Given url 'https://httpbin.org/https%3A%2F%2Fdomain'
When method get
Then status 200

这篇关于无法根据需要转义网址的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！