如何使用Kendo detailInit函数从另一个网格的不同行中获取另一个作为孩子的不同网格 [英] How to get a different grid as child from a different row of another grid using Kendo detailInit function

问题描述

我制作了一个网格，每行带有按钮，单击该按钮会打开一个弹出窗口，每个按钮上的网格都不同.

I have made a grid with buttons in each row which on-click opens a pop-up having different grids on each button.

弹出网格的每一行都可以有一个子对象(另一个只有一列的网格).如果没有孩子，则应该为空.

Each row of the pop-up grid may have a child (another grid with only one column). And if there is no child it should be empty.

因此，我正尝试使用给定示例中所示的parent-Id(PId)和(Id)来将每个子行与一个子项映射，这会将所有可用子项都排成一行，或者不将任何子项都排成一行它.

So, I'm trying to map each row with a child using parent-Id(PId) and (Id) as shown in the given example, which is taking all the available child's into a row or taking none of them into it.

Dojo示例代码

推荐答案

使用detailInit需要一种稍微不同的方法来公开属于父项的数据.您可以像这样使用e.data提取此数据:

Using detailInit requires a slightly different method of exposing the data belonging to the parent item. You can extract this data using e.data like so:

var newData2 = crdata.filter(function(ell) {
    return ell.NId == e.data.Id && ell.PId != 0;     
});

除了检查dataSource NId =父行ID并将子网格的dataSource设置移动到detailInit函数本身之外，这还可以解决问题.

That along with checking that the dataSource NId = parent row Id and moving the setup of the dataSource for the child grid into the detailInit function itself should do the trick.

Dojo示例来演示上述内容.

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