返回JSON和在Java中，Android的解析 [英] return JSON and parse in java, android

问题描述

我从PHP返回一个JSON字符串：

 ＆LT; PHP
$结果=阵列（
    结果=＆GT; 成功，
    用户名= GT; 一些用户名，
    工程=＆GT; 其他一些价值
）;回声json_en code（$结果）;
？＆GT;
 

我发现了一个Java示例网上的作品。它使用StringBuilder的输出使用吐司的响应。我想实际解析它作为一个JSON对象，所以我可以参考每个键=>值，但不知道如何去做。这是我使用的例子：

 私人无效tryLogin（字符串usernameInput，字符串passwordInput）
{
    HttpURLConnection的连接;
    OutputStreamWriter请求= NULL;
    网址URL = NULL;
    串响应=无效;
    字符串参数=用户名=+ usernameInput +＆放大器;密码=+ passwordInput;    尝试
    {
        URL =新的URL（的getString（R.string.loginLocation））;
        连接=（HttpURLConnection类）url.openConnection（）;
        connection.setDoOutput（真）;
        connection.setRequestProperty（内容类型，应用程序/ x-WWW的形式urlen codeD）;
        connection.setRequestMethod（POST）;        请求=新OutputStreamWriter（connection.getOutputStream（））;
        request.write（参数）;
        request.flush（）;
        request.close（）;
        串线=;        InputStreamReader的ISR =新的InputStreamReader（connection.getInputStream（））;
        读者的BufferedReader =新的BufferedReader（ISR）;
        StringBuilder的SB =新的StringBuilder（）;
        而（（行= reader.readLine（））！= NULL）
        {
            sb.append（行+\\ n）;
        }
        响应= sb.toString（）;        Toast.makeText（这一点，从服务器消息：\\ n+响应，0）.show（）;
        isr.close（）;
        reader.close（）;
    }
    赶上（IOException异常E）
    {
        Log.i（NetworkTest，网络错误：+ E）;
    }
}
 

这是什么code当前返回：

  05-04 19：19：54.724：信息/ NetworkTest（1061）：{结果：成功，用户名：rondog，项目： 1,2}
 

只是要清楚，我是pretty确信我知道如何解析字符串。我所困惑的是得到响应从服务器返回，推动了以JSONObject的（或者是'反应'，我传递对象？）。任何帮助是AP preciated，谢谢！

解决方案

  

（或者是'反应'，我传递对象？）

是的，是的。该公司预计它的构造函数的字符串对象来分析它。

I am returning a JSON string from PHP:

<?php
$results = array(
    "result"   => "success",
    "username" => "some username",
    "projects" => "some other value"
);

echo json_encode($results);
?>

I found a java example online that works. It uses StringBuilder and outputs the response using Toast. I want to actually parse it as a JSON object so I can reference each key=>value, but not sure how to do it. This is the example I am using:

private void tryLogin(String usernameInput, String passwordInput)
{
    HttpURLConnection connection;
    OutputStreamWriter request = null;
    URL url = null;
    String response = null;
    String parameters = "username=" + usernameInput + "&password=" + passwordInput;

    try
    {
        url = new URL(getString(R.string.loginLocation));
        connection = (HttpURLConnection) url.openConnection();
        connection.setDoOutput(true);
        connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
        connection.setRequestMethod("POST");

        request = new OutputStreamWriter(connection.getOutputStream());
        request.write(parameters);
        request.flush();
        request.close();
        String line = "";

        InputStreamReader isr = new InputStreamReader(connection.getInputStream());
        BufferedReader reader = new BufferedReader(isr);
        StringBuilder sb = new StringBuilder();
        while ((line = reader.readLine()) != null)
        {
            sb.append(line + "\n");
        }
        response = sb.toString();

        Toast.makeText(this, "Message from server: \n" + response, 0).show();
        isr.close();
        reader.close(); 
    }
    catch(IOException e)
    {
        Log.i("NetworkTest","Network Error: " + e);
    }
}

This is what the code currently returns:

05-04 19:19:54.724: INFO/NetworkTest(1061): {"result":"success","username":"rondog","projects":"1,2"}

Just to be clear, I am pretty sure I know how to parse the string. What I am confused on is getting the response back from the server and pushing that to the JSONObject (or is 'response' the object that I pass?). Any help is appreciated, thanks!

解决方案

(or is 'response' the object that I pass?)

Yes, it is. It expects a string object in it's constructor to parse it.

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