未捕获的对象错误Kendo网格读取问题 [英] Uncaught object error Kendo grid read issue
本文介绍了未捕获的对象错误Kendo网格读取问题的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是剑道新手.
我试图用远程链接中的数据创建剑道网格
I was trying to create a Kendo grid with data from a remote link
我的代码:
var dataSource = new kendo.data.DataSource({
transport: {
read: {
url: "http://www.mocky.io/v2/53e1cd17aaabaeaa0bc9a8f9",
dataType: "jsonp",
//contentType: "application/json; charset=utf-8",
}
}
});
$("#grid").kendoGrid({
dataSource: dataSource,
pageable: true,
height: 550,
editable: "inline"
});
远程链接返回的地方
[{"metaId":1,"7":"A","3":"B","10":"C","18":"D","9":"E","5":"F","2":"G","27":"A","1":"AB","6":"AD","4":"AK","20":"AL"},...]
我遇到错误
Uncaught object
为什么会出现此错误?该怎么解决?
Why am I getting this error? How to solve it?
更新
剑道上的通话示例已读
http://www.mocky.io/v2/53e1cd17aaabaeaa0bc9a8f9?callback=jQuery191038502124254591763_1407308470150&_=1407308470151
响应
jQuery191038502124254591763_1407308470150([{"metaId":1,"7":"A","3":"B","10":"C","18":"D","9":"E","5":"F","2":"G","27":"A","1":"AB","6":"AD","4":"AK","20":"AL"},{"metaId":2,"7":"A","3":"B","10":"C","18":"D","9":"E","5":"F","2":"G","27":"A","1":"AB","6":"AD","4":"AK","20":"AL"},{"metaId":3,"7":"A","3":"B","10":"C","18":"D","9":"E","5":"F","2":"G","27":"A","1":"AB","6":"AD","4":"AK","20":"AL"},{"metaId":4,"7":"A","3":"B","10":"C","18":"D","9":"E","5":"F","2":"G","27":"A","1":"AB","6":"AD","4":"AK","20":"AL"},{"metaId":5,"7":"A","3":"B","10":"C","18":"D","9":"E","5":"F","2":"G","27":"A","1":"AB","6":"AD","4":"AK","20":"AL"}]);
推荐答案
问题在于字段(列)不能为数字.这是因为在内部,如果有一个名为1
的列,它将生成为data.1
的代码,这是无效的.将您的列名称更改为有效的JavaScript字段名称,它将起作用.
The problems is that fields (columns) cannot be numbers. This is because internally, if you have a column called 1
, it generates code as data.1
which is not valid. Change your columns name to a valid JavaScript field name and it will work.
这篇关于未捕获的对象错误Kendo网格读取问题的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文