如何为字典键使用范围? [英] How to use a range for dict keys?

问题描述

我有一个程序可以扫描Google的链接，它会验证您找到了多少个链接，然后尝试为您的搜索找到成功的方法:

I have a program that scans Google for links, it verifies how many links you've found and then tries to find a success right for your search:

def check_urls_for_queries(self):
    """ The returned URLS will be run through a query regex to see if
        they have a query parameter.
          http://google.com <- False
          http://example.com/php?id=2 <- True
    """
    filename = settings.create_random_filename()
    print("File being saved to: {}".format(filename))
    with open("{}\\{}.txt".format(settings.DORK_SCAN_RESULTS_PATH, filename),
              "a+") as results:
        for url in self.connect_to_search_engine():
            match = settings.QUERY_REGEX.match(url) # Match by regex for anything
                                                    # that has a ?=<PARAM> in it
            if match:
                results.write(url + "\n")
    amount_of_urls = len(open(settings.DORK_SCAN_RESULTS_PATH + "\\" + filename
                              + ".txt", 'r').readlines())
    return("\nFound a total of {} usable links with query (GET) parameters, urls"
           " have been saved to {}\\{}.txt. This Dork has a success rate of {}%".
           format(amount_of_urls, settings.DORK_SCAN_RESULTS_PATH, filename,
                  self.success_rate[amount_of_urls]
                    if amount_of_urls in self.success_rate.keys() else
                  'Unknown success rate'))

我想做的是使用每个dict键的范围来创建成功率:

What I would like to do is create the success rate using a range per dict key:

success_rate = {
    range(1, 10): 10, range(11, 20): 20, range(21, 30): 30,
    range(31, 40): 40, range(41, 50): 50, range(51, 60): 60,
    range(61, 70): 70, range(71, 80): 80, range(81, 90): 90,
    range(91, 100): 100
}

但是显然这是行不通的，因为列表不是可哈希的对象:

However obviously this doesn't work because lists are not hashable objects:

Traceback (most recent call last):
  File "tool.py", line 2, in <module>
    from lib.core import BANNER
  File "C:\Users\Documents\bin\python\pybelt\lib\core\__init__.py", line 1, in <module>
    from dork_check import DorkScanner
  File "C:\Users\Documents\bin\python\pybelt\lib\core\dork_check\__init__.py", line 1, in <module>
    from dorks import DorkScanner
  File "C:\Users\\Documents\bin\python\pybelt\lib\core\dork_check\dorks.py", line 6, in <module>
    class DorkScanner(object):
  File "C:\Users\Documents\bin\python\pybelt\lib\core\dork_check\dorks.py", line 11, in DorkScanner
    range(1, 10): 10, range(11, 20): 20, range(21, 30): 30,
TypeError: unhashable type: 'list'

有没有办法为dict键使用范围，以免自己必须从1至100生成键?

Is there a way I could use a range for a dict key to save myself from having to make a key from 1 – 100?

推荐答案

range()仅仅是一个返回整数列表的函数，它本身并不是对象的类型.而且您不想在这里使用列表，不，因为它们包含范围内的所有整数.

range() in Python 2 is merely a function that returns a list of integers, it is not itself a type of object. And you wouldn't want to use lists here, no, because they contain all integers in the range.

您可以使用 xrange()对象，它们是可散列的，并且仅存储开始和结束值.但是，除非您打算使用 other xrange()对象测试这些键，否则带有此类键的字典不是很有用，您必须遍历字典以针对每个xrange手动对象.

You could use xrange() objects instead, these are hashable, and only store the start and end values. However, unless you plan to use other xrange() objects to test these keys, a dictionary with such keys is not very useful, you'd have to loop over the dictionary to test your rate against each xrange object manually.

您的成功率字典可以更简单地用数学代替；只需将您的数字四舍五入到最接近的10的倍数即可(只需使用下限除法即可):

Your success rate dictionary could more simply be replaced by maths; just round your numbers up to the nearest multiple of 10 (simply using floor division):

success_rate = ((amount_of_urls // 10) + 1) * 10

请测试结果值是否在10到100之间:

Do test if that resulting value is between 10 and 100:

10 <= success_rate <= 100

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