用键替换python列表元素 [英] Replacing python list elements with key

问题描述

我有一个非唯一字符串列表:

I have a list of non-unique strings:

list = ["a", "b", "c", "a", "a", "d", "b"]

我想用一个唯一标识每个字符串的整数键替换每个元素:

I would like to replace each element with an integer key which uniquely identifies each string:

list = [0, 1, 2, 0, 0, 3, 1]

数字无所谓，只要它是唯一的标识符即可.

The number does not matter, as long as it is a unique identifier.

到目前为止，我所能做的就是将列表复制到集合中，并使用集合的索引来引用列表.我敢肯定还有更好的方法.

So far all I can think to do is copy the list to a set, and use the index of the set to reference the list. I'm sure there's a better way though.

推荐答案

这将确保唯一性，并且ID从0开始是连续的:

This will guarantee uniqueness and that the id's are contiguous starting from 0:

id_s = {c: i for i, c in enumerate(set(list))}
li = [id_s[c] for c in list]

换句话说，您不应使用'list'作为变量名，因为它会遮盖内置类型list.

On a different note, you should not use 'list' as variable name because it will shadow the built-in type list.

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