精灵的对角运动 [英] Diagonal movement of a sprite

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本文介绍了精灵的对角运动的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如何实现对精灵的对角线运动?我创建了一个可移动的精灵(一个矩形),它可以在四个方向上移动.

How can I implement diagonal movement to a sprite? I created a movable sprite (a rectangle), which moves in four directions.

要对矩形进行动画处理,请使用计时器对象和执行动作的方法.我在keyPressed和keyReleased方法中实现了以下代码,以使其在四个方向上移动.

To animate the rectangle, a timer object and action performed method was used. I implemented the following code in keyPressed and keyReleased method to move it in four directions.

public void keyPressed(KeyEvent arg0){
    int c=arg0.getKeyCode();
    if(c==KeyEvent.VK_LEFT){
        velx=-4;
        vely=0;
    }
    else if(c==KeyEvent.VK_RIGHT){
        velx=4;
        vely=0;
    }
    else if(c==KeyEvent.VK_UP){
        velx=0;
        vely=-4;
    }
    else if(c==KeyEvent.VK_DOWN){
        velx=0;
        vely=4;
    }
}

public void keyReleased(KeyEvent arg0){
    velx=0;
    vely=0;
}

推荐答案

以下是基于您的最后评论的代码:

Here is code based on your last comments:

// Set of currently pressed keys
private final Set<Integer> pressed = new TreeSet<Integer>();

@Override
public void keyPressed(KeyEvent arg0) {
    int c = arg0.getKeyCode();
    pressed.add(c);
    if (pressed.size() > 1) {
        Integer[] array = pressed.toArray(new Integer[] {});
        if (array[0] == KeyEvent.VK_LEFT && array[1] == KeyEvent.VK_UP) {
            velx = -4;
            vely = -4;
        } else if (array[0] == KeyEvent.VK_UP && array[1] == KeyEvent.VK_RIGHT) {
            velx = 4;
            vely = 4;
        } else if (array[0] == KeyEvent.VK_RIGHT && array[1] == KeyEvent.VK_DOWN) {
            velx = 4;
            vely = -4;
        } else if (array[0] == KeyEvent.VK_LEFT && array[1] == KeyEvent.VK_DOWN) {
            velx = -4;
            vely = 4;
        }
    } else {
        if (c == KeyEvent.VK_LEFT) {
            velx = -4;
            vely = 0;
        } else if (c == KeyEvent.VK_RIGHT) {
            velx = 4;
            vely = 0;
        } else if (c == KeyEvent.VK_UP) {
            velx = 0;
            vely = -4;
        } else if (c == KeyEvent.VK_DOWN) {
            velx = 0;
            vely = 4;
        }
    }

}

@Override
public void keyReleased(KeyEvent arg0) {
    velx = 0;
    vely = 0;

    pressed.remove(Integer.valueOf(arg0.getKeyCode()));
}

这篇关于精灵的对角运动的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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