在列表的字典中切换键和值 [英] switch key and values in a dict of lists

问题描述

您好Stackoverflow的人，

Hello Stackoverflow people,

我有一个嵌套的字典，其中将列表作为值，并且我想创建一个dict，其中所有列表条目都将其对应的键作为值.

I have a nested dictionary with lists as values and I want to create a dict where all the list entries get their corresponding key as value.

示例时间！

# what I have
dict1 = {"A":[1,2,3], "B":[4,5,6], "C":[7,8,9]}

# what I want
dict2 = {1:"A", 2:"A", 3:"A", 4:"B", 5:"B", 6:"B", 7:"C", 8:"C", 9:"C"}

任何帮助将不胜感激！

推荐答案

尝试一下

dict1 = {"A":[1,2,3], "B":[4,5,6], "C":[7,8,9]}
dict2= {}
for keys,values in dict1.items():
    for i in values:
        dict2[i]=keys
print(dict2)

输出

{1: 'A', 2: 'A', 3: 'A', 4: 'B', 5: 'B', 6: 'B', 7: 'C', 8: 'C', 9: 'C'}

希望有帮助

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