使用变量作为关键字传递给Python中的** kwargs [英] Using variable as keyword passed to **kwargs in Python

问题描述

我有一个通过API更新记录的功能.该API接受各种可选的关键字参数:

I have a function that updates a record via an API. The API accepts a variety of optional keyword parameters:

def update_by_email(self, email=None, **kwargs):
    result = post(path='/do/update/email/{email}'.format(email=email), params=kwargs)

我还有另一个函数，该函数使用第一个函数来更新记录中的单个字段:

I have another function that uses the first function to update an individual field in the record:

def update_field(email=None, field=None, field_value=None):
    """Encoded parameter should be formatted as <field>=<field_value>"""
    request = update_by_email(email=email, field=field_value)

这不起作用.当我打电话时:

This doesn't work. When I call:

update_field(email='[e-mail]', field='name', field_value='joe')

URL编码为:

https://www.example.com/api/do/update/email/[e-mail]?field=Joe

如何将其编码为:

https://www.example.com/api/do/update/email/[e-mail]?name=Joe

谢谢.

推荐答案

除了传递名为field的参数外，您还可以使用字典解包将 field的值用作参数名称:

Rather than passing the parameter named as field, you can use dictionary unpacking to use the value of field as the name of the parameter:

request = update_by_email(email, **{field: field_value})

使用update_by_email的模拟:

def update_by_email(email=None, **kwargs):
    print(kwargs)

当我打电话

update_field("[e-mail]", "name", "joe")

我发现update_by_email中的kwargs是

{'name': 'joe'}

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