如何防止使用导航控制器按“后退"按钮后显示先前的片段? [英] How to prevent previous fragment to show up after pressing back button using navigation controller?
问题描述
我现在正在尝试使用导航控制器.我想从LoginFragment
移到HomeFragment
.在LoginFragment
中,我使用下面的代码移至HomeFragment
.
I am trying to use the navigation controller right now. I want to move from LoginFragment
to HomeFragment
. In LoginFragment
I use this code below to move to HomeFragment
.
Navigation.findNavController(view).navigate(homeDestination)
但是,当我点击HomeFragment
中的后退按钮时,它将返回到LoginFragment
,我希望当我点击按钮时它将关闭应用程序.
However, when I tap the back button in the HomeFragment
, it will go back to LoginFragment
, I expect that when I tap the button it will close the app.
以旧的方式,如果我使用活动而不是使用Fragment
,我通常会执行以下操作来获得预期的行为:
In old way, if I use activity instead of using Fragment
, I usually do something like this to get that expected behaviour:
val intent = Intent(this,HomeActivity::class.java)
intent.flags = Intent.FLAG_ACTIVITY_CLEAR_TASK.or(Intent.FLAG_ACTIVITY_NEW_TASK)
startActivity(intent)
通过使用这些标志,我用来获得预期的行为.但是我不知道如何使用导航控制器来实现相同的行为.
By using those flags, I use to get the expected behavior. But I don't how to implement the same behavior using the navigation controller.
推荐答案
Navigation提供了popUpTo
和popUpToInclusive
属性,以作为navigate()
操作的一部分从后堆栈中删除片段.
Navigation offers a popUpTo
and popUpToInclusive
attributes for removing fragments from the back stack as part of a navigate()
operation.
这可以用XML设置:
<!-- Add to your Navigation XML, then use navigate(R.id.go_home) -->
<action
android:id="@+id/go_home"
app:destination="@+id/home_fragment"
app:popUpTo="@+id/destination_to_pop"
app:popUpToInclusive="true"/>
或通过编程设置它:
NavOptions navOptions = new NavOptions.Builder()
.setPopUpTo(R.id.destination_to_pop, true)
.build();
Navigation.findNavController(view).navigate(homeDestination, navOptions)
您还可以使用<navigation>
元素的ID.
You can also use the id of a <navigation>
element as well.
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