如何在Rx中继续出现错误的流? [英] How to continue the stream with error in Rx?

查看:91
本文介绍了如何在Rx中继续出现错误的流?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用Kotlin,RxJava和Retrofit开发一个Android应用程序. 我想将Http请求发送到服务器.

I am developing an Android app using Kotlin, RxJava, Retrofit. I want to send Http Request to the server.

PUT-作业的更新选项

PUT - update option of job

POST-运行作业

第一个请求成功后,我发送第二个请求.所以我用了concatMap.

After the first request success, then I send a second request. So I used concatMap.

val updateJob = restService.updateJob(token, job.id, options) // PUT
val runJob = restService.runJob(token, job.id) // POST

updateJob.concatMap { runJob }
    .subscribeOn(Schedulers.io())
    .observeOn(AndroidSchedulers.mainThread())
    .subscribe({ job ->
        Log.d(TAG, "runJob - success: $job")
    }, {
        Log.e(TAG, "runJob - failed: ${it.message}")
        it.printStackTrace()
    })

但是我不知道是否有多个工作,如下所示.

But I don't know in case of multiple jobs like below.

我有工作清单. 如果一个作业的更新"请求失败,则不应发送运行"请求. 但是下一项工作应该继续. 为此,我编写如下代码.

I have a job list. If one job's "update" request is failed, "run" request should not be sent. But the next job should continue. To do this, I make a code like below.

    Observable.fromIterable(jobs.toList())
    .concatMap { job ->
        val updateJob = restService.updateJob(token, job.id, job)   // HTTP PUT Request
        val runJob = restService.runJob(token, job.id)  // HTTP POST Request

        updateJob.concatMap { runJob }
    }
    .window(1)
    .subscribeOn(Schedulers.io())
    .observeOn(AndroidSchedulers.mainThread())
    .subscribe({
        it.subscribeOn(Schedulers.io())
            .observeOn(AndroidSchedulers.mainThread())
            .subscribe({
                Log.e(TAG, "run job - success")
            }, {
                Log.e(TAG, "run job - failed - 1: ${it.message}")
                it.printStackTrace()
            })
    }, {
        Log.e(TAG, "run job - failed - 2: ${it.message}")
        it.printStackTrace()
    })

我认为窗口"运算符可能是解决方案. 但这不是... 如果某些作业失败,则流将通过onError()结束. 我该如何解决这个问题?

I thought that "window" operator may be the solution. But it doesn't ... If some job is failed, the stream is over with onError(). How should I solve this problem?

推荐答案

我使用以下代码解决了此问题.

I resolve this issue using the following code.

Observable.fromIterable(jobs.toList())
    .concatMap { job ->
        val updateJob = restService.updateJob(token, job.id, job)   // HTTP PUT Request
                .onErrorResumeNext(Observable.empty<Job>()) // Solution Point
        val runJob = restService.runJob(token, job.id)  // HTTP POST Request

        updateJob.concatMap { runJob }
    }
    // .window(2)    I removed this line.
    .subscribeOn(Schedulers.io())
    .observeOn(AndroidSchedulers.mainThread())
    .subscribe({
        Log.d(TAG, "run job - success")
    }, {
        Log.e(TAG, "run job - failed - 2: ${it.message}")
        it.printStackTrace()
    })

这篇关于如何在Rx中继续出现错误的流?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆