检查计算的输出是否为整数 [英] Checking if the output of a calculation is a whole number

问题描述

检查计算输出是否为整数的方法是什么?我尝试这样做:

What is a method to check if the output of a calculation is a whole number? I've tried doing this:

if ((i / 3) is Int ) {
print("Whole Number")
}

但是它似乎正在检查变量的类型，而不是输出的内容.

But it seems to be checking the type of the variable, not what the output is.

显然，如果变量是整数，它将自动舍入操作的输出，因此我必须执行以下操作:

Apparently if the variable is an integer, it automatically rounds the output of the operation, so I had to do something like this:

 if((i.toFloat()/3) == (i / 3).toFloat()){
        println("Whole Number")

推荐答案

一种简单的检查a / b是否为整数的方法是检查余数是否为零:a % b == 0.

An easy way to check whether a / b is a whole number is to check the remainder for being zero: a % b == 0.

但是，请注意，如果/的两个操作数均为整数类型(Short，Int，Long)，则除法结果将始终为整数(小数部分将被删除) )，因此，如果您有val i: Int = 2，则i % 3 == 1但i / 3 == 0.要使用分数除法，请至少对一个操作数进行分数运算，例如i / 3.0或i.toDouble / 3.

Note, however, that if both operands of / are of an integral type (Short, Int, Long), then the division result is always an integer number (the fractional part is just dropped), so, if you have a val i: Int = 2 then i % 3 == 1 but i / 3 == 0. To use fractional division, make at least one of the operands fractional like i / 3.0 or i.toDouble / 3.

如果要检查Double是否完整，可以使用d % 1.0 == 0.0或检查Math.floor(d) == d.

In case you want to check that a Double is whole, you can use d % 1.0 == 0.0 or check that Math.floor(d) == d.

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