获取字符串中唯一元素的位置[] [英] Get the positions of unique elements in a string[]
问题描述
我正在访问一个xml文件，以创建一个花费在项目上的时间的报告.我将唯一日期返回到在Winform上动态创建的标签，并希望针对每个唯一日期编译在项目上花费的时间.我已经能够返回每个日期下的所有项目或仅返回一个项目.目前，我只能返回一个项目.谁能帮帮我吗??如果正确，则数据应该是这样.
I have an xml file that I am accessing to create a report of time spent on a project. I'm returning the unique dates to a label created dynamically on a winform and would like to compile the time spent on a project for each unique date. I have been able to return all of the projects under each date or only one project. Currently I'm stuck on only returning one project. Can anyone please help me?? This is what the data should look like if it's correct.
04/11/15
26820 2.25
27111 8.00
04/12/15
26820 8.00
04/13/15
01det 4.33
26820 1.33
27225 4.25
etc.
这就是我检索数据的方式
This is how I'm retrieving the data
string[] weekDateString = elementDateWeekstring();
string[] uniqueDates = null;
string[] weeklyJobNumber = elementJobNumWeek();
string[] weeklyTicks = elementTicksWeek();
这就是我获得唯一日期的方式.
This is how I'm getting the unique dates.
IEnumerable<string> distinctWeekDateIE = weekDateString.Distinct();
foreach (string d in distinctWeekDateIE)
{
uniqueDates = distinctWeekDateIE.ToArray();
}
这就是我创建标签的方式.
And this is how I'm creating the labels.
try
{
int dateCount;
dateCount = uniqueDates.Length;
Label[] lblDate = new Label[dateCount];
int htDate = 1;
int padDate = 10;
for (int i = 0; i < dateCount; i++ )
{
lblDate[i] = new Label();
lblDate[i].Name = uniqueDates[i].Trim('\r');
lblDate[i].Text = uniqueDates[i];
lblDate[i].TabIndex = i;
lblDate[i].Bounds = new Rectangle(18, 275 + padDate + htDate, 75, 22);
targetForm.Controls.Add(lblDate[i]);
htDate += 22;
foreach (string x in uniqueDates)
{
int[] posJobNumber;
posJobNumber = weekDateString.Select((b, a) => b == uniqueDates[i].ToString() ? a : -1).Where(a => a != -1).ToArray();
for (int pjn = 0; pjn < posJobNumber.Length; pjn++)
{
if (x.Equals(lblDate[i].Text))
{
Label lblJobNum = new Label();
int htJobNum = 1;
int padJobNum = 10;
lblJobNum.Name = weeklyJobNumber[i];
lblJobNum.Text = weeklyJobNumber[i];
lblJobNum.Bounds = new Rectangle(100, 295 + padJobNum + htJobNum, 75, 22);
targetForm.Controls.Add(lblJobNum);
htJobNum += 22;
htDate += 22;
padJobNum += 22;
}
}
}
}
}
我已经坚持了大约3个月.有没有人可以向我描述为什么我无法正确检索与特定日期相关的职位编号.我不认为这些是作为日期专门返回的.只是一个看起来像日期的字符串.
I've been stuck on this for about 3 months. Is there anyone that can describe to me why I'm not able to properly retrieve the job numbers that are associated with a particular date. I don't believe that these are specifically being returned as dates. Just a string that looks like a date.
我非常感谢我能获得的任何帮助.我完全感到困惑.感谢您的任何提前答复.我非常感谢您的协助.
I really appreciate any help I can get. I'm just completely baffled. Thank you for any responses in advance. I truly appreciate the assistance.
@Sayka-这是xml示例.
@Sayka - Here is the xml sample.
<?xml version="1.0" encoding="utf-8"?>
<Form1>
<Name Key="4/21/2014 6:51:17 AM">
<Date>4/21/2014</Date>
<JobNum>26820</JobNum>
<RevNum>00000</RevNum>
<Task>Modeling Secondary</Task>
<Start>06:51 AM</Start>
<End>04:27 PM</End>
<TotalTime>345945089017</TotalTime>
</Name>
<Name Key="4/22/2014 5:44:22 AM">
<Date>4/22/2014</Date>
<JobNum>26820</JobNum>
<RevNum>00000</RevNum>
<Task>Modeling Secondary</Task>
<Start>05:44 AM</Start>
<End>06:56 AM</End>
<TotalTime>43514201221</TotalTime>
</Name>
<Name Key="4/22/2014 6:57:02 AM">
<Date>4/22/2014</Date>
<JobNum>02e-n-g</JobNum>
<RevNum>00000</RevNum>
<Task>NET Eng</Task>
<Start>06:57 AM</Start>
<End>07:16 AM</End>
<TotalTime>11706118875</TotalTime>
</Name>
....
</Form1>
这就是我从xml文件中获取信息并返回字符串[]的方式.
This is how I'm getting the information out of the xml file and returning a string[].
public static string[] elementDateWeekstring()
{
//string datetxtWeek = "";
XmlDocument xmldoc = new XmlDocument();
fileExistsWeek(xmldoc);
XmlNodeList nodeDate = xmldoc.GetElementsByTagName("Date");
int countTicks = 0;
string[] dateTxtWeek = new string[nodeDate.Count];
for (int i = 0; i < nodeDate.Count; i++)
{
dateTxtWeek[i] = nodeDate[i].InnerText;
countTicks++;
}
return dateTxtWeek;
}
作业号和滴答声以类似的方式返回.我已经在整个代码中重用了这些代码片段.这是一维xml文件?它将始终返回等于日期或刻度的职位编号的职位.我永远不会有更多或更少的任何一种元素.
Job number and Ticks are returned in a similar fashion. I've been able to reuse these snippets throught out the code. This is a one dimensional xml file?? It will always return a position for a jobnumber that equates to a date or Ticks. I will never have more or less of any one element.
推荐答案
输出是这样的
创建一个新项目
设置更大的表格大小.
应用这些代码.
设置XML文件的位置.
Set the location for your XML file.
命名空间
using System.Xml;
using System.IO;
表格代码
public partial class Form1 : Form
{
const string XML_FILE_NAME = "D:\\emps.txt";
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
prepareDataGrid();
List<JOBS> jobsList = prepareXML(XML_FILE_NAME);
for (int i = 0; i < jobsList.Count; i++)
{
addDateRow(jobsList[i].jobDate.ToString("M'/'d'/'yyyy"));
for (int j = 0; j < jobsList[i].jobDetailsList.Count; j++)
dgv.Rows.Add(new string[] {
jobsList[i].jobDetailsList[j].JobNumber,
jobsList[i].jobDetailsList[j].JobHours
});
}
}
DataGridView dgv;
void prepareDataGrid()
{
dgv = new DataGridView();
dgv.BackgroundColor = Color.White;
dgv.GridColor = Color.White;
dgv.DefaultCellStyle.SelectionBackColor = Color.White;
dgv.DefaultCellStyle.SelectionForeColor = Color.Black;
dgv.DefaultCellStyle.ForeColor = Color.Black;
dgv.DefaultCellStyle.BackColor = Color.White;
dgv.DefaultCellStyle.Alignment = DataGridViewContentAlignment.MiddleRight;
dgv.Width = 600;
dgv.Dock = DockStyle.Left;
this.BackColor = Color.White;
dgv.Columns.Add("Col1", "Col1");
dgv.Columns.Add("Col2", "Col2");
dgv.Columns[0].Width = 110;
dgv.Columns[1].Width = 40;
dgv.DefaultCellStyle.Font = new System.Drawing.Font("Segoe UI", 10);
dgv.RowHeadersVisible = dgv.ColumnHeadersVisible = false;
dgv.AllowUserToAddRows =
dgv.AllowUserToDeleteRows =
dgv.AllowUserToOrderColumns =
dgv.AllowUserToResizeColumns =
dgv.AllowUserToResizeRows =
!(dgv.ReadOnly = true);
Controls.Add(dgv);
}
void addJobRow(string jobNum, string jobHours)
{
dgv.Rows.Add(new string[] {jobNum, jobHours });
}
void addDateRow(string date)
{
dgv.Rows.Add(new string[] { date, ""});
dgv.Rows[dgv.Rows.Count - 1].DefaultCellStyle.SelectionForeColor =
dgv.Rows[dgv.Rows.Count - 1].DefaultCellStyle.ForeColor = Color.Firebrick;
dgv.Rows[dgv.Rows.Count - 1].DefaultCellStyle.Font = new Font("Segoe UI Light", 13.5F);
dgv.Rows[dgv.Rows.Count - 1].DefaultCellStyle.Alignment = DataGridViewContentAlignment.MiddleLeft;
dgv.Rows[dgv.Rows.Count - 1].Height = 25;
}
List<JOBS> prepareXML(string fileName)
{
string xmlContent = "";
using (FileStream fs = new FileStream(fileName, FileMode.Open, FileAccess.Read))
using (StreamReader sr = new StreamReader(fs)) xmlContent = sr.ReadToEnd();
XmlDocument doc = new XmlDocument();
doc.LoadXml(xmlContent);
List<JOBS> jobsList = new List<JOBS>();
XmlNode form1Node = doc.ChildNodes[1];
for (int i = 0; i < form1Node.ChildNodes.Count; i++)
{
XmlNode dateNode = form1Node.ChildNodes[i].ChildNodes[0].ChildNodes[0],
jobNumNode = form1Node.ChildNodes[i].ChildNodes[1].ChildNodes[0],
timeTicksNode = form1Node.ChildNodes[i].ChildNodes[6].ChildNodes[0];
bool foundDate = false;
for (int j = 0; j < jobsList.Count; j++) if (jobsList[j].compareDate(dateNode.Value))
{
jobsList[j].addJob(jobNumNode.Value, Math.Round(TimeSpan.FromTicks(
(long)Convert.ToDouble(timeTicksNode.Value)).TotalHours, 2).ToString());
foundDate = true;
break;
}
if (!foundDate)
{
JOBS job = new JOBS(dateNode.Value);
string jbnum = jobNumNode.Value;
string tbtck = timeTicksNode.Value;
long tktk = Convert.ToInt64(tbtck);
double tkdb = TimeSpan.FromTicks(tktk).TotalHours;
job.addJob(jobNumNode.Value, Math.Round(TimeSpan.FromTicks(
Convert.ToInt64(timeTicksNode.Value)).TotalHours, 2).ToString());
jobsList.Add(job);
}
}
jobsList.OrderByDescending(x => x.jobDate);
return jobsList;
}
class JOBS
{
public DateTime jobDate;
public List<JobDetails> jobDetailsList = new List<JobDetails>();
public void addJob(string jobNumber, string jobHours)
{
jobDetailsList.Add(new JobDetails() { JobHours = jobHours, JobNumber = jobNumber });
}
public JOBS(string dateString)
{
jobDate = getDateFromString(dateString);
}
public JOBS() { }
public bool compareDate(string dateString)
{
return getDateFromString(dateString) == jobDate;
}
private DateTime getDateFromString(string dateString)
{
string[] vals = dateString.Split('/');
return new DateTime(Convert.ToInt32(vals[2]), Convert.ToInt32(vals[0]), Convert.ToInt32(vals[1]));
}
}
class JobDetails
{
public string JobNumber { get; set; }
public string JobHours { get; set; }
}
}
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