1000位数字中五个连续数字的最大乘积 [英] Greatest product of five consecutive digits in a 1000-digit number

问题描述

我正在研究Euler项目中的问题，不确定我对这个问题的理解是否正确.

I am working through the problems on project Euler and am not too certain if my understanding of the question is correct.

问题8如下:

在1000位数字中找到五个连续数字的最大乘积.

Find the greatest product of five consecutive digits in the 1000-digit number.

我认为这是指:

我需要找到在1000位数字中连续运行的五个数字，然后将它们加起来得到总数.我假设数字的大小可以是任意值，即1,2,3或12,13,14或123,124,124或1234,1235,1236等.

I need to find any five numbers that run consecutively in the 1000 digit number and then add these up to get the total. I am assuming that the size of the numbers could be anything, i.e. 1,2,3 or 12,13,14 or 123,124,124 or 1234,1235,1236 etc.

我对此理解是否正确，还是我误解了这个问题?

Is my understanding of this correct, or have I misunderstood the question?

注意:请不要提供我需要解决的代码或解决方案.

Note: Please don't supply code or the solution, that I need to solve myself.

推荐答案

数字为:

73167176531330624919225119674426574742355349194934 96983520312774506326239578318016984801869478851843 85861560789112949495459501737958331952853208805511 12540698747158523863050715693290963295227443043557 66896648950445244523161731856403098711121722383113 62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 65727333001053367881220235421809751254540594752243 52584907711670556013604839586446706324415722155397 53697817977846174064955149290862569321978468622482 83972241375657056057490261407972968652414535100474 82166370484403199890008895243450658541227588666881 16427171479924442928230863465674813919123162824586 17866458359124566529476545682848912883142607690042 24219022671055626321111109370544217506941658960408 07198403850962455444362981230987879927244284909188 84580156166097919133875499200524063689912560717606 05886116467109405077541002256983155200055935729725 71636269561882670428252483600823257530420752963450

73167176531330624919225119674426574742355349194934 96983520312774506326239578318016984801869478851843 85861560789112949495459501737958331952853208805511 12540698747158523863050715693290963295227443043557 66896648950445244523161731856403098711121722383113 62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 65727333001053367881220235421809751254540594752243 52584907711670556013604839586446706324415722155397 53697817977846174064955149290862569321978468622482 83972241375657056057490261407972968652414535100474 82166370484403199890008895243450658541227588666881 16427171479924442928230863465674813919123162824586 17866458359124566529476545682848912883142607690042 24219022671055626321111109370544217506941658960408 07198403850962455444362981230987879927244284909188 84580156166097919133875499200524063689912560717606 05886116467109405077541002256983155200055935729725 71636269561882670428252483600823257530420752963450

• 前五个连续数字是:73167.它们的乘积是7 * 3 * 1 * 6 * 7 = 882
• 接下来的五个连续数字是:31671.它们的乘积是3 * 1 * 6 * 7 * 1 = 126
• 接下来的五个连续数字是:16717.它们的乘积是1 * 6 * 7 * 1 * 7 = 294

以此类推.注意重叠.现在，找到五个连续的数字，其乘积在整个1000位数字上最大.

And so on. Note the overlap. Now, find the five consecutive digits whose product is maximal over the whole 1000-digit number.

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