R使用apply()或lapply()或类似方法加速for循环 [英] R speed up the for loop using apply() or lapply() or etc
问题描述
我写了一个特殊的插补"函数,根据特定的列名,用均值()或mode()替换缺少(NA)值的列值.
I wrote a special "impute' function that replaces the column values that have missing (NA) values with either mean() or mode() based on the specific column name.
输入数据帧有40万行,其垂直变慢,如何使用lapply()或apply()加快插补部分.
The input dataframe is 400,000+ rows and its vert slow , how can i speed up the imputation part using lapply() or apply().
这是我要使用START OPTIMIZE& amp;优化的功能,标记部分结束优化:
Here is the function , mark section I want optimized with START OPTIMIZE & END OPTIMIZE:
specialImpute <- function(inputDF)
{
discoveredDf <- data.frame(STUDYID_SUBJID=character(), stringsAsFactors=FALSE)
dfList <- list()
counter = 1;
Whilecounter = nrow(inputDF)
#for testing just do 10 iterations,i = 10;
while (Whilecounter >0)
{
studyid_subjid=inputDF[Whilecounter,"STUDYID_SUBJID"]
vect = which(discoveredDf$STUDYID_SUBJID == studyid_subjid)
#was discovered and subset before
if (!is.null(vect))
{
#not subset before
if (length(vect)<1)
{
#subset the dataframe base on regex inputDF$STUDYID_SUBJID
df <- subset(inputDF, regexpr(studyid_subjid, inputDF$STUDYID_SUBJID) > 0)
#START OPTIMIZE
for (i in nrow(df))
{
#impute , add column mean & add to list
#apply(df[,c("y1","y2","y3","etc..")],2,function(x){x[is.na(x)] =mean(x, na.rm=TRUE)})
if (is.na(df[i,"y1"])) {df[i,"y1"] = mean(df[,"y1"], na.rm = TRUE)}
if (is.na(df[i,"y2"])) {df[i,"y2"] =mean(df[,"y2"], na.rm = TRUE)}
if (is.na(df[i,"y3"])) {df[i,"y3"] =mean(df[,"y3"], na.rm = TRUE)}
#impute using mean for CONTINUOUS variables
if (is.na(df[i,"COVAR_CONTINUOUS_2"])) {df[i,"COVAR_CONTINUOUS_2"] =mean(df[,"COVAR_CONTINUOUS_2"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_3"])) {df[i,"COVAR_CONTINUOUS_3"] =mean(df[,"COVAR_CONTINUOUS_3"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_4"])) {df[i,"COVAR_CONTINUOUS_4"] =mean(df[,"COVAR_CONTINUOUS_4"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_5"])) {df[i,"COVAR_CONTINUOUS_5"] =mean(df[,"COVAR_CONTINUOUS_5"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_6"])) {df[i,"COVAR_CONTINUOUS_6"] =mean(df[,"COVAR_CONTINUOUS_6"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_7"])) {df[i,"COVAR_CONTINUOUS_7"] =mean(df[,"COVAR_CONTINUOUS_7"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_10"])) {df[i,"COVAR_CONTINUOUS_10"] =mean(df[,"COVAR_CONTINUOUS_10"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_14"])) {df[i,"COVAR_CONTINUOUS_14"] =mean(df[,"COVAR_CONTINUOUS_14"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_30"])) {df[i,"COVAR_CONTINUOUS_30"] =mean(df[,"COVAR_CONTINUOUS_30"], na.rm = TRUE)}
#impute using mode ordinal & nominal values
if (is.na(df[i,"COVAR_ORDINAL_1"])) {df[i,"COVAR_ORDINAL_1"] =Mode(df[,"COVAR_ORDINAL_1"])}
if (is.na(df[i,"COVAR_ORDINAL_2"])) {df[i,"COVAR_ORDINAL_2"] =Mode(df[,"COVAR_ORDINAL_2"])}
if (is.na(df[i,"COVAR_ORDINAL_3"])) {df[i,"COVAR_ORDINAL_3"] =Mode(df[,"COVAR_ORDINAL_3"])}
if (is.na(df[i,"COVAR_ORDINAL_4"])) {df[i,"COVAR_ORDINAL_4"] =Mode(df[,"COVAR_ORDINAL_4"])}
#nominal
if (is.na(df[i,"COVAR_NOMINAL_1"])) {df[i,"COVAR_NOMINAL_1"] =Mode(df[,"COVAR_NOMINAL_1"])}
if (is.na(df[i,"COVAR_NOMINAL_2"])) {df[i,"COVAR_NOMINAL_2"] =Mode(df[,"COVAR_NOMINAL_2"])}
if (is.na(df[i,"COVAR_NOMINAL_3"])) {df[i,"COVAR_NOMINAL_3"] =Mode(df[,"COVAR_NOMINAL_3"])}
if (is.na(df[i,"COVAR_NOMINAL_4"])) {df[i,"COVAR_NOMINAL_4"] =Mode(df[,"COVAR_NOMINAL_4"])}
if (is.na(df[i,"COVAR_NOMINAL_5"])) {df[i,"COVAR_NOMINAL_5"] =Mode(df[,"COVAR_NOMINAL_5"])}
if (is.na(df[i,"COVAR_NOMINAL_6"])) {df[i,"COVAR_NOMINAL_6"] =Mode(df[,"COVAR_NOMINAL_6"])}
if (is.na(df[i,"COVAR_NOMINAL_7"])) {df[i,"COVAR_NOMINAL_7"] =Mode(df[,"COVAR_NOMINAL_7"])}
if (is.na(df[i,"COVAR_NOMINAL_8"])) {df[i,"COVAR_NOMINAL_8"] =Mode(df[,"COVAR_NOMINAL_8"])}
}#for
#END OPTIMIZE
dfList[[counter]] <- df
#add to discoveredDf since already substed
discoveredDf[nrow(discoveredDf)+1,]<- c(studyid_subjid)
counter = counter +1;
#for debugging to check progress
if (counter %% 100 == 0)
{
print(counter)
}
}
}
Whilecounter = Whilecounter -1;
}#end while
return (dfList)
}
谢谢
推荐答案
只要您在每个列上使用矢量化函数,就可以通过多种方式提高性能.当前,您要遍历每一行,然后分别处理每一列,这确实使您放慢了速度.另一个改进是使代码通用化,因此您不必为每个变量继续输入新行.在下面的示例中,由于连续变量是数字,而分类变量是因子,因此可以解决此问题.
It's likely that performance can be improved in many ways, so long as you use a vectorized function on each column. Currently, you're iterating through each row, and then handling each column separately, which really slows you down. Another improvement is to generalize the code so you don't have to keep typing a new line for each variable. In the examples I'll give below, this is handled because continuous variables are numeric, and categorical are factors.
要直接获得答案,您可以使用以下代码(虽然是固定变量名称)替换要优化的代码,但前提是您的数字变量不是数字变量,而序数/分类变量不是(例如因数):
To get straight to an answer, you can replace your code to be optimized with the following (though fixing variable names) provided that your numeric variables are numeric and ordinal/categorical are not (e.g., factors):
impute <- function(x) {
if (is.numeric(x)) { # If numeric, impute with mean
x[is.na(x)] <- mean(x, na.rm = TRUE)
} else { # mode otherwise
x[is.na(x)] <- names(which.max(table(x)))
}
x
}
# Correct cols_to_impute with names of your variables to be imputed
# e.g., c("COVAR_CONTINUOUS_2", "COVAR_NOMINAL_3", ...)
cols_to_impute <- names(df) %in% c("names", "of", "columns")
library(purrr)
df[, cols_to_impute] <- dmap(df[, cols_to_impute], impute)
下面是五种方法的详细比较:
Below is a detailed comparison of five approaches:
- 您最初使用
for
进行行迭代的方法;然后每列分别进行处理. - 使用
for
循环. - 使用
lapply()
. - 使用
sapply()
. - 使用
purrr
软件包中的dmap()
.
- Your original approach using
for
to iterate on rows; each column then handled separately. - Using a
for
loop. - Using
lapply()
. - Using
sapply()
. - Using
dmap()
from thepurrr
package.
所有新方法都按列对数据框进行了迭代,并使用了称为impute
的矢量化函数,该函数将均值(如果为数字)或众数插入向量中(否则).否则,它们之间的差异相对较小(如您将看到的,除了sapply()
以外),但值得检查.
The new approaches all iterate on the data frame by column and make use of a vectorized function called impute
, which imputes missing values in a vector with the mean (if numeric) or the mode (otherwise). Otherwise, their differences are relatively minor (except sapply()
as you'll see), but interesting to check.
以下是我们将使用的实用程序功能:
Here are the utility functions we'll use:
# Function to simulate a data frame of numeric and factor variables with
# missing values and `n` rows
create_dat <- function(n) {
set.seed(13)
data.frame(
con_1 = sample(c(10:20, NA), n, replace = TRUE), # continuous w/ missing
con_2 = sample(c(20:30, NA), n, replace = TRUE), # continuous w/ missing
ord_1 = sample(c(letters, NA), n, replace = TRUE), # ordinal w/ missing
ord_2 = sample(c(letters, NA), n, replace = TRUE) # ordinal w/ missing
)
}
# Function that imputes missing values in a vector with mean (if numeric) or
# mode (otherwise)
impute <- function(x) {
if (is.numeric(x)) { # If numeric, impute with mean
x[is.na(x)] <- mean(x, na.rm = TRUE)
} else { # mode otherwise
x[is.na(x)] <- names(which.max(table(x)))
}
x
}
现在,每种方法的包装函数:
Now, wrapper functions for each approach:
# Original approach
func0 <- function(d) {
for (i in 1:nrow(d)) {
if (is.na(d[i, "con_1"])) d[i,"con_1"] <- mean(d[,"con_1"], na.rm = TRUE)
if (is.na(d[i, "con_2"])) d[i,"con_2"] <- mean(d[,"con_2"], na.rm = TRUE)
if (is.na(d[i,"ord_1"])) d[i,"ord_1"] <- names(which.max(table(d[,"ord_1"])))
if (is.na(d[i,"ord_2"])) d[i,"ord_2"] <- names(which.max(table(d[,"ord_2"])))
}
return(d)
}
# for loop operates directly on d
func1 <- function(d) {
for(i in seq_along(d)) {
d[[i]] <- impute(d[[i]])
}
return(d)
}
# Use lapply()
func2 <- function(d) {
lapply(d, function(col) {
impute(col)
})
}
# Use sapply()
func3 <- function(d) {
sapply(d, function(col) {
impute(col)
})
}
# Use purrr::dmap()
func4 <- function(d) {
purrr::dmap(d, impute)
}
现在,我们将比较这些方法的性能,其中n的范围为10到100(非常小):
Now, we'll compare the performance of these approaches with n ranging from 10 to 100 (VERY small):
library(microbenchmark)
ns <- seq(10, 100, by = 10)
times <- sapply(ns, function(n) {
dat <- create_dat(n)
op <- microbenchmark(
ORIGINAL = func0(dat),
FOR_LOOP = func1(dat),
LAPPLY = func2(dat),
SAPPLY = func3(dat),
DMAP = func4(dat)
)
by(op$time, op$expr, function(t) mean(t) / 1000)
})
times <- t(times)
times <- as.data.frame(cbind(times, n = ns))
# Plot the results
library(tidyr)
library(ggplot2)
times <- gather(times, -n, key = "fun", value = "time")
pd <- position_dodge(width = 0.2)
ggplot(times, aes(x = n, y = time, group = fun, color = fun)) +
geom_point(position = pd) +
geom_line(position = pd) +
theme_bw()
很明显,原始方法要比在每一列上使用矢量化功能impute
的新方法慢得多.新产品之间的差异如何?让我们加大样本量以进行检查:
It's pretty clear that the original approach is much slower than the new approaches that use the vectorized function impute
on each column. What about differences between the new ones? Let's bump up our sample size to check:
ns <- seq(5000, 50000, by = 5000)
times <- sapply(ns, function(n) {
dat <- create_dat(n)
op <- microbenchmark(
FOR_LOOP = func1(dat),
LAPPLY = func2(dat),
SAPPLY = func3(dat),
DMAP = func4(dat)
)
by(op$time, op$expr, function(t) mean(t) / 1000)
})
times <- t(times)
times <- as.data.frame(cbind(times, n = ns))
times <- gather(times, -n, key = "fun", value = "time")
pd <- position_dodge(width = 0.2)
ggplot(times, aes(x = n, y = time, group = fun, color = fun)) +
geom_point(position = pd) +
geom_line(position = pd) +
theme_bw()
看起来像sapply()
并不好(就像@Martin指出的那样).这是因为sapply()
正在做额外的工作来使我们的数据变成矩阵形状(我们不需要).如果您自己不使用sapply()
来运行此程序,则会看到其余方法都具有相当的可比性.
Looks like sapply()
is not great (as @Martin pointed out). This is because sapply()
is doing extra work to get our data into a matrix shape (which we don't need). If you run this yourself without sapply()
, you'll see that the remaining approaches are all pretty comparable.
因此,主要的性能改进是在每列上使用向量化函数.我建议一开始使用dmap
,因为我通常是函数样式和purrr
包的爱好者,但是您可以轻松地替换任何喜欢的方法.
So the major performance improvement is to use a vectorized function on each column. I suggested using dmap
at the beginning because I'm a fan of the function style and the purrr
package generally, but you can comfortably substitute for whichever approach you prefer.
此外,非常感谢@Martin的非常有用的评论,这使我得以改善此答案!
Aside, many thanks to @Martin for the very useful comment that got me to improve this answer!
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