Laravel在单个子句中使用多个where和sum [英] Laravel use multiple where and sum in single clause

问题描述

在我的数据库中，我有instagram_actions_histories表，该表中有action_type列，在该列中，我有不同的数据，例如1或2或3

in my database i have instagram_actions_histories table which into that i have action_type column, in the column i have unlike data such as 1 or 2 or 3

例如，我试图获取关系表中的该表数据并求和该值，这些值存储在列中

i'm trying to get this table data in relation ship and summing this values which stored in column, for example

$userAddedPagesList = auth()->user()->instagramPages()->with([
        'history' => function ($query)  {
            $query->select(['action_type as count'])->whereActionType(1)->sum('action_type');
        }
    ]
)->get();

顺便说一句，此代码是不正确的，因为我要在其中包含所有sum的所有history

btw, this code is not correct, in that i want to get all history with multiple sum inside that

whereActionType(1)->sum('action_type')
whereActionType(2)->sum('action_type')
whereActionType(3)->sum('action_type')

例如(伪代码):

$userAddedPagesList = auth()->user()->instagramPages()->with([
        'history' => function ($query)  {
            $query->select(['action_type as like'])->whereActionType(1)->sum('action_type');
            $query->select(['action_type as follow'])->whereActionType(2)->sum('action_type');
            $query->select(['action_type as unfollow'])->whereActionType(3)->sum('action_type');
        }
    ]
)->get();

更新:

$userAddedPagesList = auth()->user()->instagramPages()->with([
        'history' => function ($query) {
            $query->select('*')
                ->selectSub(function ($query) {
                    return $query->selectRaw('SUM(action_type)')
                        ->where('action_type', '=', '1');
                }, 'like')
                ->selectSub(function ($query) {
                    return $query->selectRaw('SUM(action_type)')
                        ->where('action_type', '=', '2');
                }, 'follow')
                ->selectSub(function ($query) {
                    return $query->selectRaw('SUM(action_type)')
                        ->where('action_type', '=', '3');
                }, 'followBack');
        }
    ]
)->get();

错误:

Syntax error or access violation: 1140 Mixing of GROUP columns (MIN(),MAX(),COUNT(),...) with no GROUP columns is illegal if there is no GROUP BY clause (SQL: select *, (select SUM(action_type) where `action_type` = 1) as `like`, (select SUM(action_type) where `action_type` = 2) as `follow`, (select SUM(action_type) where `action_type` = 3) as `followBack` from `instagram_actions_histories` where `instagram_actions_histories`.`account_id` in (1, 2, 3))

我如何实现此解决方案?

how can i implementing this solution?

更新:

InstagramAccount类:

class InstagramAccount extends Model
{
    ...

    public function schedule()
    {
        return $this->hasOne(ScheduleInstagramAccounts::class, 'account_id');
    }

    public function history()
    {
        return $this->hasMany(InstagramActionsHistory::class, 'account_id');
    }
}

InstagramActionsHistory类:

class InstagramActionsHistory extends Model
{
    protected $guarded=['id'];

    public function page(){
        return $this->belongsTo(InstagramAccount::class);
    }
}

用户类别:

class User extends Authenticatable
{
    use Notifiable;

    ...

    public function instagramPages()
    {
        return $this->hasMany(InstagramAccount::class);
    }
}

推荐答案

另一种获取不同类型操作的条件和的方法，您可以在InstagramAccount模型中定义hasOne()关系，例如

Another approach to get conditional sum for your different types of action, you can define a hasOne() relation in your InstagramAccount model like

public function history_sum()
{
    return $this->hasOne(InstagramActionsHistory::class, 'account_id')
        ->select('account_id',
            DB::raw('sum(case when action_type = 1 then 0 END) as `like`'),
            DB::raw('sum(case when action_type = 2 then 0 END) as `follow`'),
            DB::raw('sum(case when action_type = 3 then 0 END) as `followBack`')
        )->groupBy('account_id');
}

那么您可以急于将相关数据加载为

Then you can eager load the related data as

$userAddedPagesList = auth()->user()->instagramPages()->with('history_sum')->get();

使用此方法将仅执行一个额外的查询，以根据您的条件获得3个不同的总和结果

Going through with this approach will execute only one extra query to get 3 different sum results based on your criteria

select `account_id`,
sum(case when action_type = 1 then action_type else 0 END) as `like`, 
sum(case when action_type = 2 then action_type else 0 END) as `follow`, 
sum(case when action_type = 3 then action_type else 0 END) as `followBack` 
from `instagram_actions_histories` 
where `instagram_actions_histories`.`account_id` in (?, ?, ?) 
group by `account_id`

尽管与使用withCount的其他方法相比(这也是一个有效的答案)，将为每种操作类型添加3个相关的相关子查询，这可能会导致性能开销，但生成的查询如下所示

While as compare to other approach (which is a valid answer also) using withCount will add 3 dependent correlated sub queries for each action type which may result as a performance overhead, generated query will look something like below

select `instagram_account`.*, 
(select sum(action_type) from `instagram_actions_histories` where `instagram_account`.`id` = `instagram_actions_histories`.`account_id` and `action_type` = ?) as `like`, 
(select sum(action_type) from `instagram_actions_histories` where `instagram_account`.`id` = `instagram_actions_histories`.`account_id` and `action_type` = ?) as `follow`,
(select sum(action_type) from `instagram_actions_histories` where `instagram_account`.`id` = `instagram_actions_histories`.`account_id` and `action_type` = ?) as `followBack`
from `instagram_account` 
where `instagram_account`.`user_id` = ? 
and `instagram_account`.`user_id` is not null

要检查生成的查询，请参考 Laravel 5.3-如何在页面上记录所有查询?

To check the generated queries refer to Laravel 5.3 - How to log all queries on a page?

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