Laravel 5.2带有可变参数的命名路由用法 [英] Laravel 5.2 named route usage with variable parameter

问题描述

我有一条这样的路线:

// Open New Subscription page
Route::get('/account/subscriptions/create/{menu}', ['uses' => 'Subscriptions\SubscriptionController@create', 'as' => 'subscription.create']);

在刀片模板中，我使用如下命名的路由:

In my blade template I use the named route like this:

<a href="{!! route('organisations.index') . "/p11-c3" !!}">

但是这种格式不起作用.

But this format does not work.

如何在仍使用命名路由的情况下为变量菜单传递一个值(而不是在href中硬编码url)?

How do I pass the variable menu a value while still using the named route (rather than hard coding a url in the href)?

推荐答案

您可以将路由参数作为第二个参数传递给 route()帮助器:

You can pass your route parameters as the second argument to route() helper:

<a href="{!! route('organisations.index', ['menu' => 'p11-c3']) !!}">

确保使用正确的名称.路由定义了 subscription.create 路由，而模板引用了 organisations.index 路由.

Make sure you're using correct names. Your routing defines subscription.create route while your template refers to organisations.index route.

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