Laravel 4,-> withInput(); =未定义偏移量:0 [英] Laravel 4, ->withInput(); = Undefined offset: 0
问题描述
我在这里和Laravel论坛上都进行了冗长的搜索,但是我找不到这个问题的答案. ->withInput()
咳嗽Undefined offset: 0
.
I have had a lengthy search both here and the Laravel forums, but i can't find an answer to this problem. ->withInput()
coughs up an Undefined offset: 0
.
对于上下文:
控制器
public function getJobs()
{
$position_options = DB::table('jposition')->lists('friendly','id');
$category_options = DB::table('jcategory')->lists('friendly','id');
$location_options = DB::table('jlocation')->lists('friendly','id');
$result = $query->get();
return View::make('jobsearch.search', array('position_options' => $position_options, 'category_options' => $category_options, 'location_options' => $location_options))->withInput();
}
查看
<form action="{{ action('JobsearchController@getJobs') }}" method="post">
<div class="row">
<div class="large-8 columns">
<input type="text" name="realm" placeholder="Keywords/Skills" />
</div>
<div class="large-4 columns">
{{ Form::select('category', $category_options , Input::old('category')) }}
</div>
</div>
<div class="row">
<div class="large-4 columns">
{{ Form::select('location', $location_options , Input::old('location')) }}
</div>
<div class="large-4 columns">
{{ Form::select('type', $position_options , Input::old('type')) }}
</div>
<div class="large-4 columns">
<input type="submit" value="Search" style="width:100%; padding-top: .5rem;
padding-bottom: .5rem;" class="button border-btn" />
</div>
</div>
</form>
现在,根据文档,这里应该没有问题,并且如果删除了->withInput();
,则页面可以正常加载.
Now according to the documentation there should not be an issue, and the page loads fine if the ->withInput();
is removed.
最终目标是加入我从上一个问题中得到的答案 db的不良结果: raw ,只有一个页面可以加载过滤"表单,并在重新加载时显示相关结果,并记住表单中的选择.
The end goal is to roll in the answer that i received from my previous question Undesired result from db:raw and have a single page that loads the "Filtering" form and displays the relevant results on the reload and remembers the selections in the form.
谢谢.
更新: 发表评论后,我已经更新了控制器和路由,结果仍然相同:
UPDATE: Following a comment i have updated the controller and routes, still same result:
routes.php
routes.php
Route::get('jobs/search', 'JobsearchController@getSearch');
&
Route::post('jobs/search', 'JobsearchController@getJobs');
控制器
public function getSearch()
{
$position_options = DB::table('jposition')->lists('friendly','id');
$category_options = DB::table('jcategory')->lists('friendly','id');
$location_options = DB::table('jlocation')->lists('friendly','id');
return View::make('jobsearch.search', array('position_options' => $position_options, 'category_options' => $category_options, 'location_options' => $location_options));
}
public function getJobs()
{
$position_options = DB::table('jposition')->lists('friendly','id');
$category_options = DB::table('jcategory')->lists('friendly','id');
$location_options = DB::table('jlocation')->lists('friendly','id');
return View::make('jobsearch.search', array('position_options' => $position_options, 'category_options' => $category_options, 'location_options' => $location_options))->withInput();
}
推荐答案
withInput()
不能以您认为的方式工作.它只是重定向的功能,而不是View的功能.
withInput()
doesn't work the way you think it does. It's only a function of Redirect, not View.
在View上调用withInput($data)
具有完全不同的效果;它将以下键值对传递给您的视图:'input' => $data
(由于未将任何数据传递给该函数而出现错误)
Calling withInput($data)
on View has a completely different effect; it passes the following key value pair to your view: 'input' => $data
(you get an error because you're not passing any data to the function)
要获得所需的效果,请在生成视图之前调用Input::flash()
,而不要调用withInput()
.这样一来,您就可以在视图中使用Input::old()
函数来访问数据.
To get the effect that you want, call Input::flash()
before making your view, instead of calling withInput()
. This should allow you to use the Input::old()
function in your view to access the data.
或者,您可以简单地将Input::all()
传递到视图,并在视图中使用input[]
数组:
Alternatively, you could simply pass Input::all()
to your view, and use the input[]
array in your view:
View::make(...)->withInput(Input::all());
翻译成
View::make(...)->with('input', Input::all());
关于您的评论,我建议这样做:
As for your comment, I recommend doing it like so:
$position_options = DB::table('jposition')->lists('friendly','id');
$category_options = DB::table('jcategory')->lists('friendly','id');
$location_options = DB::table('jlocation')->lists('friendly','id');
$category = Input::get('category');
$location = Input::get('location');
$type = Input:: get('type');
$data = compact('position_options', 'category_options', 'location_options', 'category', 'type', 'location');
return View::make('jobsearch.search', $data);
这篇关于Laravel 4,-> withInput(); =未定义偏移量:0的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!