Laravel 4:使用数据嵌套布局内的视图 [英] Laravel 4: Nest view inside layout with data
本文介绍了Laravel 4:使用数据嵌套布局内的视图的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在编写一个仅依赖一些路线和视图的简单应用程序.我已经设置了总体布局,并使用以下内容成功嵌套了模板.
I'm writing a simple app which only relies on a few routes and views. I've setup an overall layout and successfully nested a template using the following.
routes.php
View::name('layouts.master', 'master');
$layout = View::of('master');
Route::get('/users', function() use ($layout)
{
$users = Users::all()
return $layout->nest('content','list-template');
});
master.blade.php
<h1>Template</h1>
<?=$content?>
list-template.php
foreach($users as $user) {
echo $user->title;
}
如何将查询结果 $ users 传递到我的主模板中,然后传递到list-temple.php中?
How do I pass the query results $users into my master template and then into list-temple.php?
谢谢
推荐答案
->nest
允许数据数组的第三个参数:
->nest
allows a 3rd argument for an array of data:
Route::get('/users', function() use ($layout)
{
$users = Users::all()
return $layout->nest('content','list-template', array('users' => $users));
});
也在您的master.blade.php文件中-将其更改为:
Also in your master.blade.php file - change it to this:
<h1>Template</h1>
@yield('content')
list-template.blade.php<-注意刀片的文件名:
list-template.blade.php <- note the blade filename:
@extends('layouts.master')
@section('content')
<?php
foreach($users as $user) {
echo $user->title;
}
?>
@stop
这篇关于Laravel 4:使用数据嵌套布局内的视图的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文