如何在Laravel 4中使用参数和CASE语句进行更新查询 [英] How to make update query with parameters and CASE statement in Laravel 4

问题描述

我正在尝试创建将采用参数的mysql UPDATE查询.另外，如果该字段不为空，我想附加到该字段的末尾.为此，我正在使用CASE语句. 这是我对学说的查询(来自silex):

I'm trying to create mysql UPDATE query that will take parameters. In addition I want to append to the end of the field if the field isnt empty. For that I'm using CASE statement. Here's my query in doctrine (from silex):

$query = "UPDATE table SET filed = (
CASE WHEN field = ''
THEN :param1
ELSE concat(field, :param1)
END)
WHERE id=:param2";
$app['db']['test_db']->executeUpdate($sql, array('param1' => $user_text, 'param2' => $selected_id));

现在，我想将其转换为流利的查询或原始查询，以便可以在Laravel 4中使用它.

Now I want to convert it to fluent or raw query so I can use it in Laravel 4.

这是我的代码:

$param1 = "String..."; // user string
$param2 = 45; // id
DB:connection('test_db')->statement("UPDATE table SET field =(
case
    WHEN field=''
    THEN $param1 
    ELSE concat(field, $param1)
END)
WHERE id=$param2");

当我在Laravel中执行此查询时，我会看到

When I execute this query in Laravel I see

语法错误或访问冲突:1064

Syntax error or access violation: 1064

任何帮助将不胜感激.

推荐答案

尝试使用raw()运行它:

DB::statement(
    DB::raw(
                "UPDATE table SET field =
                    (
                        CASE
                            WHEN field=''
                            THEN ?
                            ELSE concat(field, ?)
                        END
                    )
                    WHERE id=?"
    ),

    array($param1, $param1, $param2)
);

这篇关于如何在Laravel 4中使用参数和CASE语句进行更新查询的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！