如何在Laravel中定义默认的后备路由? [英] How do I define a default fallback route in Laravel?

问题描述

我目前正在将自定义CMS从Laravel 3升级到Laravel 4(出于各种原因，这一升级很重要).

I'm currently upgrading a custom CMS from Laravel 3 to Laravel 4 (this upgrade is important for various reasons).

在现有版本中，它已经设置了路由，以便可以分别定义路由-但是，如果有人尝试加载未明确定义的路由，则系统会捕获该路由并将其发送到页面处理器"- -实质上检查数据库中是否存在CMS页面/帖子.

In the existing version, it has routing set up so that routes can be individually defined--but if someone tries to load a route that is not specifically defined, the system catches it and sends it to a "page processor"--which essentially checks to see if the CMS page/post exists in the database.

Laravel 3中的后备"或默认"路由处理行如下所示:

The "fallback" or "default" route processing line in Laravel 3 looked like this:

Route::get('(.*)', array('uses' => 'myPageLoading@method'));

我的问题是Laravel 4不支持此语法.如何在Laravel 4中做到这一点?

My problem is that this syntax is not supported in Laravel 4. How do I do this in Laravel 4?

推荐答案

知道了.

Laravel 4语法:

Route::any('{all}', array('uses' => 'myPageLoading@method'))->where('all', '.*');

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