如何在LINQ的添加两个列表，以便addedList [X] =那么listOne [X] + listTwo [X] [英] How do I add two lists in Linq so addedList[x] = listOne[x] + listTwo[x]?

问题描述

我想补充一个数字类型，这样的两个列表 addedList [X] =那么listOne [X] + listTwo [X]

列表的输出必须是Generic.IEnumerable我可以在将来LINQ查询使用。

当我能够用低于code做到这一点，我不禁觉得必须有一个更好的办法。任何想法？

 名单，其中，INT＆GT; firstList =新列表与所述; INT＆GT;（新INT [] {1，3，4，2，5,7，2，5，7，8，9，0}）;
名单＆LT; INT＆GT; secondList =新列表与所述; INT＆GT;（新INT [] {4,6，8,3，1,5，9,3，0}）;

INT findex = 0;

ILookup＆LT; INT，INT＆GT; flookup = firstList.ToLookup（F =＆GT;
                            {
                               INT I = findex;
                               findex ++;
                               返回我;
                               }，p值=＆GT; p）的;

VAR listsAdded =从GRP在flookup
                 选择grp.First（）+ secondList.ElementAtOrDefault（grp.Key）;

的foreach（诠释我在listsAdded）
  Console.WriteLine（ⅰ）;
 

解决方案

  VAR的结果=
   从我在
        Enumerable.Range（0，Math.Max​​（firstList.Count，secondList.Count））
   选择firstList.ElementAtOrDefault（我）+ secondList.ElementAtOrDefault（我）;
 

I want to add two lists of a numeric type such that addedList[x] = listOne[x] + listTwo[x]

The output of the list needs to be a Generic.IEnumerable that I can use in future linq queries.

While I was able to do it using the code below, I can't help but feel like there must be a better way. Any ideas?

List<int> firstList = new List<int>(new int[] { 1, 3, 4, 2, 5, 7, 2, 5, 7, 8, 9, 0 });
List<int> secondList = new List<int>(new int[] { 4, 6, 8, 3, 1, 5, 9, 3, 0 });

int findex = 0;

ILookup<int, int> flookup = firstList.ToLookup(f =>
                            {
                               int i = findex;
                               findex++; 
                               return i;
                               }, p => p);  

var listsAdded = from grp in flookup
                 select grp.First() + secondList.ElementAtOrDefault(grp.Key);

foreach (int i in listsAdded)
  Console.WriteLine(i);

解决方案

var result = 
   from i in 
        Enumerable.Range(0, Math.Max(firstList.Count, secondList.Count))
   select firstList.ElementAtOrDefault(i) + secondList.ElementAtOrDefault(i);

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