如何阅读PHP code的响应到Android的Java code [英] How to read response of php code to android java code

问题描述

我有返回数据库中的所有内容作为一个JSON数组WAMP的服务器上运行一个PHP code。我想我的Andr​​oid应用程序连接到这个PHP文件。我如何获得这个PHP文件到Android的Java code的响应。

我的PHP code：

 ＆LT; PHP$ CON = mysqli_connect（localhost的根，2015，testdatabase）或死亡（错误mysqli_error（$链接）。）;
如果（！$ CON）
{
死亡（无法连接：'mysqli_error（））;
}
$结果= mysqli_query（$ CON，SELECT * FROM客户）;
而（$行= mysqli_fetch_assoc（$结果））
{
$输出[] = $行;
}
打印（json_en code（$输出））;
mysqli_close（$ CON）;
？＆GT;
 

另外这里是我目前在做我的Andr​​oid code（但大多数我在做什么被视为德precated）：

 公共JSONArray GetAllCustomers（）
    {
        // URL获取所有客户
        字符串URL =htt​​p://127.0.0.1/Customers/getAllCustomers.php;        //获取的Htt presponse从URL对象。
        //从HTTP响应对象HttpEntity        HttpEntity httpEntity = NULL;        尝试
        {            DefaultHttpClient的HttpClient =新DefaultHttpClient（）; //默认的HttpClient
            HTTPGET HTTPGET =新HTTPGET（URL）;            HTT presponse HTT presponse = httpClient.execute（HTTPGET）;            httpEntity = HTT presponse.getEntity（）;        }赶上（ClientProtocolException E）{            //在HTTP协议信号的错误
            e.printStackTrace（）;            //登录错误在这里        }赶上（IOException异常五）{
            e.printStackTrace（）;
        }
        //转换HttpEntity成JSON阵列
        JSONArray jsonArray = NULL;        如果（httpEntity！= NULL）{
            尝试{
                字符串entityResponse = EntityUtils.toString（httpEntity）;                Log.e（实体回应：entityResponse）;                jsonArray =新JSONArray（entityResponse）;            }赶上（JSONException E）{
                e.printStackTrace（）;
            }赶上（IOException异常五）{
                e.printStackTrace（）;
            }
        }        返回jsonArray;    }
}
 

解决方案

我也可以根据这个教程与Android连接PHP Web服务（JSON格式）。我认为它也会对你有所帮助。

如何与And​​roid的PHP连接， MySQL的

I have a php code running on a wamp server which returns all the contents of database as a JSON array. I want to connect my android app to this php file. How do i get the response of this php file to my android java code.

MY PHP CODE:

<?php

$con = mysqli_connect("localhost","root","2015","testdatabase") or die("Error " . mysqli_error($link));
if (!$con)
{
die('Could not connect: ' . mysqli_error());
}
$result = mysqli_query($con,"SELECT * FROM Customer");
while($row = mysqli_fetch_assoc($result))
{
$output[]=$row;
}
print(json_encode($output));
mysqli_close($con);
?>

Also here is what I'm currently doing in my android code (But most of what i am doing is deemed deprecated):

public JSONArray GetAllCustomers()
    {
        // URL for getting all customers


        String url = "http://127.0.0.1/Customers/getAllCustomers.php";

        // Get HttpResponse Object from url.
        // Get HttpEntity from Http Response Object

        HttpEntity httpEntity = null;

        try
        {

            DefaultHttpClient httpClient = new DefaultHttpClient();  // Default HttpClient
            HttpGet httpGet = new HttpGet(url);

            HttpResponse httpResponse = httpClient.execute(httpGet);

            httpEntity = httpResponse.getEntity();



        } catch (ClientProtocolException e) {

            // Signals error in http protocol
            e.printStackTrace();

            //Log Errors Here



        } catch (IOException e) {
            e.printStackTrace();
        }


        // Convert HttpEntity into JSON Array
        JSONArray jsonArray = null;

        if (httpEntity != null) {
            try {
                String entityResponse = EntityUtils.toString(httpEntity);

                Log.e("Entity Response  : ", entityResponse);

                jsonArray = new JSONArray(entityResponse);

            } catch (JSONException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }

        return jsonArray;

    }


}

解决方案

I also connect php web services(Json formatted) with android according to this tutorial. I think it will also helpful to you also.

How to connect Android with PHP, MySQL

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