libgdx Shaperenderer线..如何绘制具有特定宽度的线 [英] libgdx Shaperenderer line .. How to draw line with a specific width

问题描述

我正在尝试使用libgdx形状渲染器绘制特定宽度的线.我遵循了这个链接

问题是如果我指定更多的线宽，即大于9，它不会显示增加的宽度.如果我指定20或100像素以上，则会有9个以上的结果

shapeRenderer.begin(ShapeType.Line);
    shapeRenderer.line(50, 70, 0, 50, 200, 0, Color.BLUE, Color.RED);
    int lineWidth = 20; // pixels
    Gdx.gl10.glLineWidth(lineWidth / camera.zoom);
     shapeRenderer.end();

谢谢 摇摇车

解决方案

查询支持的宽度范围和之间的大小差异 范围内支持的宽度，请使用参数调用glGet GL_ALIASED_LINE_WIDTH_RANGE，GL_SMOOTH_LINE_WIDTH_RANGE和 GL_SMOOTH_LINE_WIDTH_GRANULARITY.

参考

为避免特定于设备的行为，我改用四边形.从小纹理上绘制一个1x1的正方形，然后定位，缩放(取决于要绘制的线条的宽度和高度)，着色并旋转它.

I am trying to draw a line of specific width using libgdx shape renderer. I followed this link

The problem is if i specify more line width i.e more than 9 it does not show increased width. More than 9 either i specify 20 or 100 pixels it will have the same result as 9

shapeRenderer.begin(ShapeType.Line);
    shapeRenderer.line(50, 70, 0, 50, 200, 0, Color.BLUE, Color.RED);
    int lineWidth = 20; // pixels
    Gdx.gl10.glLineWidth(lineWidth / camera.zoom);
     shapeRenderer.end();

Thanks Shakeel

解决方案

To query the range of supported widths and the size difference between supported widths within the range, call glGet with arguments GL_ALIASED_LINE_WIDTH_RANGE, GL_SMOOTH_LINE_WIDTH_RANGE, and GL_SMOOTH_LINE_WIDTH_GRANULARITY.

Reference

To avoid device specific behavior, I use a quad instead. Draw a 1x1 square from a small texture and then position, scale (depending on the width and height of the line you wanted to draw), color, and rotate it.

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