LIBSVM训练数据格式(svm_problem中svm_node中的x值) [英] LIBSVM training data format (x values in svm_node for svm_problem)

问题描述

我正在使用LIBSVM以编程方式进行简单的XOR分类，试图了解这些功能的工作原理.我已按照自述文件中的说明尽可能地设置了问题.使用svm_predict(总是1或-1)时，我仍然得到错误的输出.

I am using LIBSVM to do a simple XOR classification programmatically, trying to understand how the functions work. I have set up the problem following the instructions in the Readme as close as possible. Still i get the wrong output when using svm_predict (always 1 or -1).

在一个相关的问题中，有人建议在使用很少的培训示例时可能会出现此问题.我尝试将示例数量增加到20，但这没有帮助.

In a related question somebody suggested that the problem might arise when using very few training examples. I tried increasing the number of examples to 20 but this did not help.

我怀疑问题出在prob.x和/或prob.y的定义中，但是无法理解在哪里.您能否帮助阐明如何使用svm_node定义prob.x和prob.y?

I suspect that the problem is somewhere in the definition of prob.x and/or prob.y but can't understand where. Could you help clarify how to define prob.x and prob.y using svm_node?

我已经进行了彻底搜索，但找不到答案... 此处 此处 此处 此处.

I hade searched thoroughly but cannot find an answer... E.g. Here, here, here, here, and here.

提前谢谢！

这是我的代码:

//Parameters
svm_parameter param;
param.svm_type = C_SVC;
param.kernel_type = RBF;
param.degree = 3;
param.gamma = 0;
param.coef0 = 0;
param.nu = 0.5;
param.cache_size = 100;
param.C = 0.4;
param.eps = 1e-3;
param.p = 0.1;
param.shrinking = 1;
param.probability = 0;
param.nr_weight = 0;
param.weight_label = NULL;
param.weight = NULL;



//Problem definition
svm_problem prob;


//Length
prob.l = 4;                             //number of training examples


//x values

svm_node** x = new svm_node *[prob.l];  //Array of pointers to pointers to arrays

svm_node* x_space1 = new svm_node[3];   //Fist training example
svm_node* x_space2 = new svm_node[3];   //Second training example
svm_node* x_space3 = new svm_node[3];   //Third training example
svm_node* x_space4 = new svm_node[3];   //Fourth training example

x_space1[0].index = 1;                  //Fist training example
x_space1[0].value = 1;
x_space1[1].index = 2;
x_space1[1].value = 1;
x_space1[2].index = -1;

x_space2[0].index = 1;                  //Second training example
x_space2[0].value = 1;
x_space2[1].index = 2;
x_space2[1].value = 0;
x_space2[2].index = -1;

x_space3[0].index = 1;                  //Third training example
x_space3[0].value = 0;
x_space3[1].index = 2;
x_space3[1].value = 1;
x_space3[2].index = -1;

x_space4[0].index = 1;                  //Fourth training example
x_space4[0].value = 0;
x_space4[1].index = 2;
x_space4[1].value = 0;
x_space4[2].index = -1;

x[0] = x_space1;                        //Set each training example to x
x[1] = x_space2;
x[2] = x_space3;
x[3] = x_space4;

prob.x = x;                             //Assign x to the struct field prob.x


//yvalues
prob.y = new double[prob.l];
prob.y[0] = -1;
prob.y[1] = 1;
prob.y[2] = 1;
prob.y[3] = -1;


//Train model
svm_model *model = svm_train(&prob,&param);


//Test model
svm_node* testnode = new svm_node[3];
testnode[0].index = 1;
testnode[0].value = 1;
testnode[1].index = 2;
testnode[1].value = 0;
testnode[2].index = -1;

double retval = svm_predict(model,testnode);
qDebug()<<retval;                               //Should return +1 but returns -1

推荐答案

您的参数似乎有问题.例如，如果您使用的是RBF内核，则param.gamma不应为零.

It seems a problem with your parameters. For instance, param.gamma shouldn't be zero if you are using a RBF kernel.

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