延长线程变量的生命周期 [英] Extend lifetime of a variable for thread

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本文介绍了延长线程变量的生命周期的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在从文件中读取字符串,将其按行拆分为向量,然后要对提取的行在单独的线程中进行某些处理.像这样:

I am reading a string from a file, splitting it by lines into a vector and then I want to do something with the extracted lines in separate threads. Like this:

use std::fs::File;
use std::io::prelude::*;
use std::thread;
fn main() {
    match File::open("data") {
        Ok(mut result) => {
            let mut s = String::new();
            result.read_to_string(&mut s);
            let k : Vec<_> = s.split("\n").collect();
            for line in k {
                thread::spawn(move || {
                    println!("nL: {:?}", line);
                });
            }

        }
        Err(err) => {
            println!("Error {:?}",err);
        }
    }
}

这当然会引发错误,因为s将在启动线程之前超出范围:

Of course this throws an error, because s will go out of scope before the threads are started:

s` does not live long enough
main.rs:9           let k : Vec<_> = s.split("\n").collect();
                                     ^

我现在该怎么办?我已经尝试了许多类似BoxArc的方法,但是我无法使其正常工作.我以某种方式需要创建一个s的副本,该副本也存在于线程中.但是我该怎么做?

What can I do now? I've tried many things like Box or Arc, but I couldn't get it working. I somehow need to create a copy of s which also lives in the threads. But how do I do that?

推荐答案

从根本上讲,问题是lines的借用片段.在这里您实际上无能为力,因为无法保证每个line都不会超过s本身.

The problem, fundamentally, is that line is a borrowed slice into s. There's really nothing you can do here, since there's no way to guarantee that each line will not outlive s itself.

另外,要清楚一点:Rust中绝对没有办法 延长变量的生命周期".根本做不到.

Also, just to be clear: there is absolutely no way in Rust to "extend the lifetime of a variable". It simply cannot be done.

解决此问题的最简单方法是从被借用的line变为拥有的 .像这样:

The simplest way around this is to go from line being borrowed to owned. Like so:

use std::thread;
fn main() {
    let mut s: String = "One\nTwo\nThree\n".into();
    let k : Vec<String> = s.split("\n").map(|s| s.into()).collect();
    for line in k {
        thread::spawn(move || {
            println!("nL: {:?}", line);
        });
    }
}

.map(|s| s.into())&str转换为String.由于String拥有其内容,因此可以安全地将其移动到每个线程的闭包中,并且独立于创建它的线程而存在.

The .map(|s| s.into()) converts from &str to String. Since a String owns its contents, it can be safely moved into each thread's closure, and will live independently of the thread that created it.

注意:您可以使用新的作用域线程API在每晚Rust中执行此操作,但这仍然不稳定.

Note: you could do this in nightly Rust using the new scoped thread API, but that is still unstable.

这篇关于延长线程变量的生命周期的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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