如何从HashSet形成切片? [英] How do I form a slice from a HashSet?

查看:66
本文介绍了如何从HashSet形成切片?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

结构定义为:

struct Node {
    set: HashSet<usize>,
    // other fields omitted
}

必须实现特征(兼容性问题)的功能,该特征需要将集合中的所有元素作为切片返回.

I have to implement a function for a trait (compatibility issues) which needs to return all elements in the set as a slice.

我知道以下功能无法正常工作:

I am aware of something like the following function won't work:

impl Node {
    pub fn set_slice(&self) -> &[usize] {
        let elems: Vec<_> = self.set.iter().cloned().collect();
        &elems[..]
    }
}

问题是:

error[E0597]: `elems` does not live long enough
  --> src/main.rs:11:10
   |
11 |         &elems[..]
   |          ^^^^^ borrowed value does not live long enough
12 |     }
   |     - borrowed value only lives until here
   |
note: borrowed value must be valid for the anonymous lifetime #1 defined on the method body at 9:5...
  --> src/main.rs:9:5
   |
9  | /     pub fn set_slice(&self) -> &[usize] {
10 | |         let elems: Vec<_> = self.set.iter().cloned().collect();
11 | |         &elems[..]
12 | |     }
   | |_____^

我知道这个要求听起来很奇怪.尽管我为什么要做这个,但有没有好的"方法来实现呢?

I know this requirement may sound strange. Despite why I have to do this, is there any 'good' way to achieve this?

如果可能的话,我想保留HashSet容器以进行O(1)查找,并且我不想引入新的struct成员以节省内存.

If it is possible, I want keep the HashSet container for a O(1) lookup, and I don't want to introduce new struct members in order to save memory.

推荐答案

不,在安全的Rust中,您的要求是100%完全不可能的.

No, your requirements are 100% completely impossible in safe Rust.

A HashSet/HashMap没有连续的数据收集,因此无法从中获取切片.

A HashSet / HashMap do not have a contiguous collection of data, thus there's no way to get a slice from them.

如果您可以进行更改,则可以选择.

If you can change things, then you have options.

如果可以存储Vec并且方法为&mut self,则可以呈现" HashSet的视图:

You can "render a view" of the HashSet if you can store a Vec and the method is &mut self:

struct Node {
    set: HashSet<usize>,
    view: Vec<usize>,
    // other fields omitted
}

impl Node {
    pub fn set_slice(&mut self) -> &[usize] {
        self.view.clear();
        self.view.extend(self.set.iter().cloned());
        &self.view
    }
}

您可以返回借用或拥有的Cow:

You could return a Cow which would be either borrowed or owned:

use std::borrow::Cow;

impl Node {
    pub fn set_slice(&self) -> Cow<[usize]> {
        self.set.iter().cloned().collect::<Vec<_>>().into()
    }
}

您可以在值上返回迭代器:

impl Node {
    pub fn set_slice<'a>(&'a self) -> impl Iterator<Item = &'a usize> + 'a {
        self.set.iter()
    }
}

有一个可能 一个板条箱,它使用紧密包装的Vec作为其包装支持存储,然后可以将其公开为切片.

There's possibly a crate that uses a tightly-packed Vec as its backing storage, which could then be exposed as a slice.

这篇关于如何从HashSet形成切片?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆