特质较高的等级限制和盒装封口寿命问题 [英] Higher Ranked Trait Bound and boxed closures lifetime issue

问题描述

我正在尝试编写一个函数，该函数返回一个盒装的闭包，该闭包可以处理对任何类型的引用 一生.在编写特定实例时，一切正常.但是当写一个泛型 版本，我遇到一生的问题.

I am trying to write a function returning a boxed closure that can work on references to types with any lifetime. When writing a specific instance, everything works fine. But when writing a generic version, I run into lifetime problems.

struct Parameter<'a> {
    s: &'a str,
}

fn main() {
    let closure = generate_closure_gen();
    let string = String::from("Hello World!");
    let parameter = Parameter { s: &string }; // Error: string does not live long enough
    closure(&parameter);
}

// This one works fine
// Desugared version for Box<Fn(&Parameter)>
fn generate_closure() -> Box<for <'a, 'r> Fn(&'r Parameter<'a>)> {
    Box::new(|c: &Parameter| {})
}

// This one gives lifetime errors
fn generate_closure_gen<C>() -> Box<Fn(&C)> {
    Box::new(|c: &C| {})
}

我不明白为什么闭包需要type参数的生存期比它更长(没有存储空间或其他任何东西……).它适用于HRTB的非通用版本，只是感觉应该有可能使其与通用版本一起使用.
另外，如果我尝试使用通用版本编写特定版本，则会出现类型错误

I don't see why the closure needs the type parameter to live longer than it (there is no storage or anything ...). And it works for the non-generic version with HRTB, it just feels like it should be possible to make it work with the generic version.
Also, if I try to write the specific version using the generic version, I get a type error

// Desugared version for Box<Fn(&Parameter)>
fn generate_closure_2() -> Box<for <'a, 'r> Fn(&'r Parameter<'a>)> {
    generate_closure_gen()
}

src/main.rs:22:5: 22:27 error: mismatched types:
 expected `Box<for<'r, 'r> core::ops::Fn(&'r Parameter<'r>) + 'static>`,
    found `Box<for<'r> core::ops::Fn(&'r _) + 'static>`
(expected concrete lifetime,
    found bound lifetime parameter ) [E0308]
src/main.rs:22     generate_closure_gen()
                   ^~~~~~~~~~~~~~~~~~~~~~
src/main.rs:22:5: 22:27 help: run `rustc --explain E0308` to see a detailed explanation

关于如何进行这项工作的任何想法?

Any idea on how to make this work?

(游戏围栏链接)

推荐答案

类型参数具有生存期限制.该生命周期限制是实现者所有生命周期参数中最短的.您在generate_closure_gen上省略了它，所以编译器会推断出它，但是如果我们明确地将其写出，函数定义将如下所示:

Type parameters have a lifetime bound. That lifetime bound is the shortest of all of the implementor's lifetime parameters. You omitted it on generate_closure_gen, so the compiler inferred it, but if we explicitly wrote it out, the function definition would look like this:

fn generate_closure_gen<'a, C: 'a>() -> Box<Fn(&C)> {
    Box::new(|c: &C| {})
}

但是，进行此更改并不能解决我们的问题.

Making this change doesn't solve our problem, though.

要了解原因，我们需要弄清楚C是什么.您用&'y Parameter<'x>调用闭包，闭包接受for<'b> &'b C，因此C是Parameter<'x>. Parameter<'x>有一个生存期参数，它将对C上的生存期产生影响.

To understand why, we need to figure out what C is inferred to be. You call the closure with a &'y Parameter<'x>, and the closure accepts for<'b> &'b C, so C is Parameter<'x>. Parameter<'x> has a lifetime parameter, which will have an influence on the lifetime bound on C.

泛型函数中的生存期参数必须替换为在函数调用之前开始的生存期.在这种情况下，这意味着我们传递给闭包的任何C的生存期必须在调用generate_closure_gen之前有效.这是因为C绑定到特定的生存期，而不是任何生存期.即C为Parameter<'x>时，必须事先知道'x；每次调用闭包时，我们都不能使用不同的'x.换句话说，您希望拥有的是这样的东西:

Lifetime parameters in generic functions must be substituted with lifetimes that start before the function call. In this case, this means that the lifetime of any C we pass to the closure must be valid before the call to generate_closure_gen. That's because C is bound to a specific lifetime, not to any lifetime; i.e. when C is Parameter<'x>, the 'x must be known in advance; we can't have a different 'x each time we call the closure. In other words, what you'd like to have is something like this:

fn generate_closure_gen<C: for<'a> 'a>() -> Box<Fn(&C)> {
    Box::new(|c| {})
}

但是不幸的是，从Rust 1.7开始这是不合法的.

But unfortunately, that isn't legal as of Rust 1.7.

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