需要根据日期拉最后x行数 [英] Need to pull last x number of rows based on date

问题描述

我有一张表格，其中的日期为"2009年8月23日"格式，并且有5个值，因此看起来像这样

I have a table with dates in "Aug 23, 2009" format and 5 values, so that it looks like this

SELECT * FROM table;
Date         | Total | V1 | V2 | V3 | V4   
Aug 21, 2009 | 41    | 23 | 8  | 8  | 2
Aug 22, 2009 | 39    | 22 | 8  | 7  | 2
Aug 23, 2009 | 35    | 20 | 6  | 7  | 2
Aug 24, 2009 | 34    | 20 | 6  | 6  | 2
Aug 25, 2009 | 32    | 19 | 5  | 6  | 2
Aug 26, 2009 | 31    | 19 | 5  | 5  | 2
Aug 27, 2009 | 30    | 19 | 5  | 5  | 1

所以我需要一个查询，该查询将只给我最新的(底部)3个条目.我应该按日期设置一些查询还是只对最后3行设置一个限制?我尝试执行一个具有限制的子查询，但是我的MySQL版本不支持子查询中的LIMIT，据我所知，没有办法对负的最后一行数进行负限制.

So I need a query that will give me only the most recent (bottom) 3 entries. Should I setup some query by the date or just set a limit to the last 3 rows? I tried doing a subquery with a limit, but my version of MySQL does not support LIMIT in subquery, and to my knowledge there is no way to do a negative limit to grab the last x number of rows.

推荐答案

select *
from table 
order by Date desc
limit 0, 3

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