sed删除除前5个行外的其余字符 [英] sed delete remaining characters in line except first 5

问题描述

使用sed，sed命令将删除行中除前5个前导字符之外的所有字符的命令? 我尝试对此进行后退"(还原删除)，但这并不是最优雅的解决方案.

what would be sed command to delete all characters in line except first 5 leading ones, using sed? I've tried going 'backwards' on this (reverted deleting) but it's not most elegant solution.

推荐答案

这可能对您有用(GNU sed):

This might work for you (GNU sed):

echo '1234567890' | sed 's/.//6g'
12345

或者:

echo '1234567890' | cut -c-5
12345

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