ARG_SECTION_NUMBER不能得到解决 [英] ARG_SECTION_NUMBER cannot be resolved

问题描述

目前，我正在试图创建3种不同的片段，3种不同的标签具有为每个标签不同内容的目的。我卡在我的code一些错误，说：

  

ARG_SECTION_NUMBER不能解析

 公共类SampleFragmentPagerAdapter扩展FragmentPagerAdapter {
最终诠释PAGE_COUNT = 3;私人字符串tabTitles [] =新的String [] {特色，浏览，继};私人上下文的背景下;公共SampleFragmentPagerAdapter（FragmentManager FM，上下文的背景下）{
    超（FM）;
    this.context =背景;
}@覆盖
公众诠释的getCount（）{
    返回PAGE_COUNT;
}@覆盖
公共片段的getItem（INT位置）{
    //（原编码）返回PageFragment.newInstance（位置+ 1）;    //的getItem被称为实例化片段为给定的页面。
    //返回一个DummySectionFragment（定义为静态内部类
    //下面）附页码为它的独立参数。
    开关（位置）{
        情况下0：
            片段片段=新DummySectionFragment（）;
            捆绑ARGS =新包（）;
            args.putInt（fragment.ARG_SECTION_NUMBER，位置+ 1）;
            fragment.setArguments（参数）;
            返回片段;        情况1：
            片段fragment2 =新DummySectionFragment2（）;
            捆绑args2 =新包（）;
            //args2.putInt(fragment2.ARG_SECTION_NUMBER，位置+ 2）;
            fragment2.setArguments（args2）;
            返回fragment2;        案例2：            片段fragment3 =新DummySectionFragment3（）;
            捆绑args3 =新包（）;
            //args3.putInt(fragment3.ARG_SECTION_NUMBER，位置+ 3）;
            fragment3.setArguments（args3）;
            返回fragment3;
        默认：
            返回null;
    }}@覆盖
公共CharSequence的getPageTitle（INT位置）{
    //根据项目位置生成标题
    //（原编码）返回tabTitles [位置]    区域设置L = Locale.getDefault（）;
    开关（位置）{
        情况下0：
            返回App.getContext（）的getString（R.string.title_section1）.toUpperCase（1）。;
        情况1：
            返回App.getContext（）的getString（R.string.title_section2）.toUpperCase（1）。;
        案例2：
            返回App.getContext（）的getString（R.string.title_section3）.toUpperCase（1）。;
    }
    返回null;}
 

}

任何人有任何想法，为什么ARGS_SECTION_NUMBER不能

解决

• fragment.ARG_SECTION_NUMBER


• fragment2.ARG_SECTION_NUMBER


• fragment3.ARG_SECTION_NUMBER

的DummySectionFragment.java如下：

 公共类DummySectionFragment扩展片段{
/ **
 *片段参数重新presenting本节号
 *片段。
 * /
公共静态最后弦乐ARG_SECTION_NUMBER =section_number_1;
公共DummySectionFragment（）{}
@覆盖
公共查看onCreateView（LayoutInflater充气器，容器的ViewGroup，
                         捆绑savedInstanceState）{
    查看rootView = inflater.inflate（R.layout.fragment_main，集装箱，FALSE）;
    TextView的dummyTextView =（TextView中）rootView.findViewById（R.id.section_label）;
    dummyTextView.setText（Integer.toString（getArguments（）调用getInt（ARG_SECTION_NUMBER）））;
    返回rootView;
}
 

}

解决方案

这是因为你的片段变量的类型片段。但恒定在DummySectionFragment限定。所以，你需要做的是：

  args.putInt（DummySectionFragment.ARG_SECTION_NUMBER，位置+ 1）;
 

请记住，当你使用一些类文件中定义的常量，没有必要通过类的实例来访问它们。

I'm currently trying to create 3 different tabs with 3 different fragments for the purpose of having different content for each tab. I'm stuck with some error in my code that says :

ARG_SECTION_NUMBER cannot be resolved

public class SampleFragmentPagerAdapter extends FragmentPagerAdapter {
final int PAGE_COUNT = 3;

private String tabTitles[] = new String[] { "Featured", "Browse", "Following" };

private Context context;

public SampleFragmentPagerAdapter(FragmentManager fm, Context context) {
    super(fm);
    this.context = context;
}

@Override
public int getCount() {
    return PAGE_COUNT;
}

@Override
public Fragment getItem(int position) {
    //(original coding) return PageFragment.newInstance(position + 1);

    //getItem is called to instantiate the fragment for the given page.
    // Return a DummySectionFragment (defined as a static inner class
    // below) with the page number as its lone argument.
    switch (position) {
        case 0:
            Fragment fragment = new DummySectionFragment();
            Bundle args = new Bundle();
            args.putInt(fragment.ARG_SECTION_NUMBER, position + 1);
            fragment.setArguments(args);
            return fragment;

        case 1:
            Fragment fragment2 = new DummySectionFragment2();
            Bundle args2 = new Bundle();
            //args2.putInt(fragment2.ARG_SECTION_NUMBER, position + 2);
            fragment2.setArguments(args2);
            return fragment2;

        case 2:

            Fragment fragment3 = new DummySectionFragment3();
            Bundle args3 = new Bundle();
            //args3.putInt(fragment3.ARG_SECTION_NUMBER, position + 3);
            fragment3.setArguments(args3);
            return fragment3;


        default:
            return null;
    }

}

@Override
public CharSequence getPageTitle(int position) {
    // Generate title based on item position
    //(original coding) return tabTitles[position];

    Locale l = Locale.getDefault();
    switch (position) {
        case 0:
            return App.getContext().getString(R.string.title_section1).toUpperCase(l);
        case 1:
            return App.getContext().getString(R.string.title_section2).toUpperCase(l);
        case 2:
            return App.getContext().getString(R.string.title_section3).toUpperCase(l);
    }
    return null;

}

}

Anyone have any idea why ARGS_SECTION_NUMBER cannot be resolved for

• fragment.ARG_SECTION_NUMBER
• fragment2.ARG_SECTION_NUMBER
• fragment3.ARG_SECTION_NUMBER

The DummySectionFragment.java is as follows:

public class DummySectionFragment extends Fragment {
/**
 * The fragment argument representing the section number for this
 * fragment.
 */
public static final String ARG_SECTION_NUMBER = "section_number_1";
public DummySectionFragment() {

}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {
    View rootView = inflater.inflate(R.layout.fragment_main, container, false);
    TextView dummyTextView = (TextView) rootView.findViewById(R.id.section_label);
    dummyTextView.setText(Integer.toString(getArguments().getInt(ARG_SECTION_NUMBER)));
    return rootView;
}

}

解决方案

This is because your fragment variable has type Fragment. But constant is defined in DummySectionFragment. So what you need to do is:

 args.putInt(DummySectionFragment.ARG_SECTION_NUMBER, position + 1);

Remember that when you use constants defined in some class file, there's no need to access them via instance of the class.

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