使用LINQ从复杂的XML中提取数据 [英] Extracting data from a complex XML with LINQ
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问题描述
我的目标是将ValueReference节点,TimeInstant属性和timePosition节点中包含的数据保存到变量中.我能够获取valueReference节点的值(未注释的部分有效),但无法获取其他两个值. 任何帮助将不胜感激.
My goal is to save the data contained in the ValueReference node, TimeInstant attribute, and timePosition node into variables. I am able to get the value of the valueReference node (the un-commented section works), but not the other two. Any help would be greatly appreciated.
这是我正在处理的代码:
Here is the code that I am working on:
public void LinqToXml()
{
XNamespace sosNamespace = XNamespace.Get("http://www.opengis.net/sos/2.0");
XNamespace fesNamespace = XNamespace.Get("http://www.opengis.net/fes/2.0");
XNamespace gmlNamespace = XNamespace.Get("http://www.opengis.net/gml/2.0");
var root = XElement.Load(@"C:\Working Directory\OGCSOS.Service\OGCSOS.Service\Resources\GetObservation_TemporalFilter.xml");
var a = (from level in root.Descendants(sosNamespace + "temporalFilter")
select new
{
valueReference = (string)level.Descendants(fesNamespace + "After")
.Elements(fesNamespace + "ValueReference")
.First(),
/*timeInstant = (string)level.Descendants(fesNamespace + "After")
.Elements(gmlNamespace + "TimeInstant")
.Attributes(gmlNamespace + "id")
.First()*/
/*timePosition = (string)level.Descendants(fesNamespace + "After")
.Elements(gmlNamespace + "TimeInstant")
.First()*/
}).ToList();
这是我要阅读的XML:
And here is the XML I am trying to read:
<?xml version="1.0" encoding="UTF-8"?>
<sos:GetObservation xmlns="http://www.opengis.net/sos/2.0" service="SOS" version="2.0.0"
xmlns:sos="http://www.opengis.net/sos/2.0" xmlns:fes="http://www.opengis.net/fes/2.0"
xmlns:gml="http://www.opengis.net/gml/3.2" xmlns:swe="http://www.opengis.net/swe/2.0"
xmlns:swes="http://www.opengis.net/swes/2.0" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.opengis.net/sos/2.0
http://schemas.opengis.net/sos/2.0/sos.xsd">
<!--identifier of an offering-->
<offering>HG.Logger@DJK001</offering>
<!--identifier of an observed property-->
<observedProperty>HG</observedProperty>
<!--optional temporal filter restricting the results which shall be returned-->
<temporalFilter>
<fes:After>
<fes:ValueReference>phenomenonTime</fes:ValueReference>
<gml:TimeInstant gml:id="startPosition">
<gml:timePosition>2008-03-01T17:44:15.000+00:00</gml:timePosition>
</gml:TimeInstant>
</fes:After>
</temporalFilter>
<featureOfInterest>DJK001</featureOfInterest>
</sos:GetObservation>
推荐答案
将您的gml命名空间更改为
Your gml namespace is not correct, after changing it to
XNamespace gmlNamespace = XNamespace.Get("http://www.opengis.net/gml/3.2");
您可以使用
timeInstant = level.Descendants(fesNamespace + "After")
.First()
.Element(gmlNamespace + "TimeInstant")
.Attribute(gmlNamespace + "id")
.Value,
timePosition = level.Descendants(fesNamespace + "After")
.First()
.Element(gmlNamespace + "TimeInstant")
.Value
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