pp(PAR)在哪里解压缩添加(-a)文件? [英] Where does pp (PAR) unpack add (-a) files?

问题描述

这是我尝试解决所引起的无关紧要的问题为什么我的系统调用在用pp包装的Perl程序中不起作用? "我已经在linux系统上创建了一个简单的Perl脚本:

This is my attempt to cut through extraneous issues raised "Why don’t my system calls work in the Perl program I wrap with pp?" I have created a simple Perl script on a linux system:

new-net:~/scripts # cat ls_test.pl
@ls_out = `ls -l`;

map { print "$_\n" } @ls_out;

$out = `sh out_test.sh`;

print "$out\n";

此脚本调用一个简单的外壳文件:

This script calls a simple shell file:

new-net:~/scripts # cat out_test.sh
echo "I'm here"

我用pp将Perl脚本和Shell脚本打包到ls_test中:

I used pp to pack the Perl script along with the shell script into ls_test:

new-net:~/test # unzip -l ls_test
Archive:  ls_test
  Length     Date   Time    Name
 --------    ----   ----    ----
        0  07-13-09 16:41   script/
      436  07-13-09 16:41   MANIFEST
      214  07-13-09 16:41   META.yml
       93  07-13-09 16:41   script/ls_test.pl
      538  07-13-09 16:41   script/main.pl
       16  07-13-09 16:20   out_test.sh
 --------                   -------
     1297                   6 files

如果我在一个原本为空的目录中运行打包文件，则找不到shell脚本:

If I run the packed file in an otherwise empty directory, the shell script is not found:

new-net:~/test # ./ls_test
total 3391

-rwxr-xr-x 1 root root 3466177 Jul 13 16:41 ls_test

sh: out_test.sh: No such file or directory

如果我将shell脚本复制到目录中，则打包的脚本将按预期运行:

If I copy the shell script into the directory, the packed script runs as expected:

new-net:~/test # ./ls_test

total 3395

-rwxr-xr-x 1 root root 3466177 Jul 13 16:41 ls_test
-rw-r--r-- 1 root root      16 Jul 13 16:20 out_test.sh

I'm here

那么，pp打包脚本应该在哪里找到包含的文件?以及如何在原始Perl脚本中配置对该包含文件的调用?

So, where does a pp packed script expect to find an included file? And how should a call to that included file be configured in the original Perl script?

推荐答案

打包的可执行文件中的文件被提取到一个临时目录(通常为/tmp/par-USERNAME/cache-XXXXXXX). 要访问这些文件，请执行以下操作:

The files in a packaged executable are extracted to a temporary directory (usually /tmp/par-USERNAME/cache-XXXXXXX). To access these files do something like the following:

#!/usr/bin/perl

# Reads a data file from the archive (added with -a)
print PAR::read_file("data");

# Will execute "script2" in the archive and exit. Will not return to this script.
require PAR;
PAR->import( { file => $0, run => 'script2' } );

您还可以建立与可执行文件具有相同名称的可执行文件的符号链接，然后运行它们.

You can also make symolic links to the executable that have the same name as the script you want to run, and run those.

实际上，重读您的问题，仅访问PAR_TEMP环境变量可能更有用:

Actually, rereading your question, simply accessing the PAR_TEMP environment variable is probably more useful:

#!/usr/bin/perl
use File::Slurp qw(slurp);

$data_dir = "$ENV{PAR_TEMP}/inc";
$script_dir = "$data_dir/script";

print slurp("$data_dir/datafile");

# file access permissions are not preserved as far as I can tell,
# so you'll have to invoke the interpreter explicitly.
system 'perl', "$script_dir/script2", @args;

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