在fork和exec之后在父级和子级之间共享文件描述符 [英] Share a file descriptor between parent and child after fork and exec
问题描述
我在Linux上有两个进程,即A& B.
我想与进程B共享进程A的文件描述符,现在我将其序列化为char*
并将其传递给execl
参数,但这不起作用.
I have two processes on Linux, A & B.
I want to share the file descriptor from process A with process B, now I just serialize it to a char*
and pass it to the execl
parameters, but that doesn't work.
A.c看起来像这样:
A.c looks like this:
union descriptor{
char c[sizeof(int)];
int i;
} fd;
pid_t pid;
fd.i = socket(AF_INET, SOCK_STREAM, IPPROTO_TCP);
// Perform other socket functions
pid = fork();
if(pid == 0){
// Read data from socket
if(execl("./B", fd.c, NULL) < 0){
exit(EXIT_FAILURE);
}else(
exit(EXIT_SUCCESS);
}
}else if(pid < 0){
exit(EXIT_FAILURE);
}else{
waitpid(pid, NULL, 0);
}
B.c看起来像这样:
B.c looks like this:
union descriptor{
char c[sizeof(int)];
int i;
} fd;
memcpy(&fd.c[0], argv[0], sizeof(int));
write(fd.i, "TEST", 4);
close(fd.i);
但这是行不通的,而且我真的不明白为什么不这样做.我该如何进行这项工作?如果可行,在fork
和exec
之后在父子之间共享文件描述符的最佳解决方案吗?
But this doesn't work, and I don't really understand why not. How can I make this work? And if it works, is it the best solution to share a file descriptor between a parent and a child after a fork
and a exec
?
该问题与我提出的问题无关,这是由@OliCharlesworth指出的传递整数的错误方式引起的.请关闭此问题.
The problem is unrelated to the question I asked, it is caused by a wrong way of passing an integer as pointed out by @OliCharlesworth. Please close this question.
推荐答案
File descriptors are always passed between a parent and child process
当您fork
一个进程时,在父级中打开的文件描述符(在fork()
时)将隐式传递给子级.无需显式发送它们.
When you fork
a process, the file descriptors that are open in the parent(at the time of fork()
) are implicitly passed on to the child. There is no need to send them explicitly.
例如:
伪代码如下:
进行中 A :
fd = open_socket_or_file;
char str_fd[3];
str_fd[0]=fd;
str_fd[1]=fd;
str_fd[2]=0;
if(fork()==0)
{
execl("./B",str_fd,NULL);
}
在子进程 B 中,您可以执行以下操作:
In the child process B you can do:
int fd = argv[1][0];
/* now do whatever you want with the fd...*/
如果过程不同,则需要显式传递文件描述符.通常使用UNIX域套接字完成此操作(如果您使用的是Linux Flavors).有关与此相关的代码,您可以参见此答案
In case the processes are different, you need to pass the file descriptor explicitly. This is generally done using UNIX-Domain Sockets(If you are using Linux Flavors). For code related to this, you can see this answer
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