卷曲命令以重复URL请求 [英] Curl Command to Repeat URL Request

问题描述

Linux命令重复击中URL次数x的语法是什么?我不需要对数据做任何事情，只需要在浏览器中复制击中刷新20次即可.

Whats the syntax for a linux command that hits a URL repeatedly, x number of times. I don't need to do anything with the data, I just need to replicate hitting refresh 20 times in a browser.

推荐答案

您可以使用带有伪查询字符串的URL序列替换(如果您想使用CURL并保存一些击键):

You could use URL sequence substitution with a dummy query string (if you want to use CURL and save a few keystrokes):

curl http://www.myurl.com/?[1-20]

如果您的URL中还有其他查询字符串，请将序列分配给一个一次性变量:

If you have other query strings in your URL, assign the sequence to a throwaway variable:

curl http://www.myurl.com/?myVar=111&fakeVar=[1-20]

在手册页上查看URL部分: https://curl.haxx.se/docs/manpage.html

Check out the URL section on the man page: https://curl.haxx.se/docs/manpage.html

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