启用Android应用程序连接到互联网 [英] Enable Android App to Connect to the Internet
问题描述
我一直在使用Phohegap检索一些记录使用下面的index.html FRM的远程数据库中创建一个简单的应用程序：
I have created a simple app using Phohegap to retrieve few records frm a remote database using the following index.html:
<!doctype html>
<html><head>
<meta charset="utf-8">
<title>Untitled Document</title>
<link rel="stylesheet" type="text/css" href="jquery.mobile-1.4.4.min.css">
<script src="jquery-1.11.1.min.js"></script>
<script src="jquery.mobile-1.4.4.min.js"></script>
<script charset="utf−8" type="text/javascript">
function connect(e)
{
var term= {button:e};
$.ajax({
url:'http://dubaisinan.host22.com/reply.php',
type:'POST',
data:term,
dataType:'json',
error:function(jqXHR,text_status,strError){
alert("No Connection");},
timeout:60000,
success:function(data){
$("#result").html("");
for(var i in data){
$("#result").append("<li>"+data[i]+"</li>");
}
}
});
}
</script>
</head>
<body>
<center><b>My Students</b></center>
<center><input onclick="connect(this.value)" type="button" value="showStudents" /></center>
<center><b>Results</b></center>
<ul data-role="listview" id="result"></ul>
</body>
</html>
和以下reply.php：
And the following reply.php:
<?php
header('Content-Type: application/json');
$link = mysql_connect('host_name', 'user-name', 'password');
if (!$link)
{
$myStudents[] = "No";
die('Could not connect: ' . mysql_error());
}
mysql_select_db("a2808249_db1",$link);
$result = mysql_query("SELECT * FROM Students",$link);
while ($myrow = mysql_fetch_row($result))
{
$myStudents[] = $myrow[1];
}
print json_encode($myStudents);
?>
它可以在我的笔记本电脑正常，但当我建立它使用的PhoneGap和下载我的注3设备上的apk文件，我收到消息无连接。看来这个应用程序是无法连接到互联网。该器件具有互联网连接。
It works fine on my laptop but when I build it using Phonegap and download the apk file on my Note 3 device, I receive the message "No Connection". It seems that the app is not able to connect to the Internet. The device has Internet connection.
任何帮助吗？
思南
Any help please? Sinan
推荐答案
添加这些行
<script type="text/javascript" charset="utf-8" src="cordova.js"></script>
<script type="text/javascript" charset="utf-8">
另外你说你要检索，所以这应该是一个GET调用，而不是POST。
Also you said you want to retrieve, so this should be a GET call , not POST.
也可以使用＆LT;！DOCTYPE HTML＆GT; （正确的编码标准）
Also use <!DOCTYPE html> (proper coding standard)
编辑：范例中得到调用
$.ajax({
url: "http://abcd.com",
headers: {
"X-API-KEY": "2b9asdedqedqxdqd7956e6f7a",
"Content-Type": "application/json"
},
type: "GET",
data: fromDatan,
dataType: "JSON",
success: function(fromData, status, jqXHR) {
alert(JSON.stringify(fromData));
},
error: function(jqXHR, status) {
alert(JSON.stringify(jqXHR));
}
});
编辑：这是一个示例code，可以发布到测试服务器
<!DOCTYPE html>
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.min.js"></script>
<script language="javascript" type="text/javascript">
<!--
function greeter() {
var accx = 5;
var accy = 6;
var accz = 7;
var output = [];
output[0] = {
name: "Accel_X",
value: accx.toString(), // retrieve x
};
output[1] = {
name: "Accel_Y",
value: accy.toString(), // retrieve y
};
output[2] = {
name: "Accel_Z",
value: accz.toString() // retrieve z
};
var fromData = {};
fromData.output = output;
var fromDatan = JSON.stringify(fromData);
alert(fromDatan);
jQuery.ajax({
url: "http://posttestserver.com/post.php",
type: "POST",
data: fromDatan,
dataType: "JSON",
success: function(fromDatan, status, jqXHR) {
alert(JSON.stringify(fromData));
},
error: function(jqXHR, status) {
alert(JSON.stringify(jqXHR));
}
/*
error:function(jqXHR,text_status,strError){
alert("No Connection");},
timeout:60000,
success:function(data){
$("#result").html("");
for(var i in data){
$("#result").append("<li>"+data[i]+"</li>");
}
}*/
});
return false;
}
//-->
</script>
</head>
<body>
<button onclick="greeter();">Click me</button>
</body>
</html>
我试着用你的网址，而不是工作。但是会让你知道，如果我能
I tried with your url, not working. However will let you know if I can
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