更新终端上显示的文本 [英] Updating text displayed on the terminal

问题描述

我正在尝试用C语言创建生活游戏程序，但是我对更新终端上显示的输出的过程不是很熟悉.

I'm attempting to create a game of life program in C, but i'm not very familiar with a process to update the output displayed on the terminal.

因此，例如，我将拥有一个2d char数组，其中每个元素将包含一个#"或一个-".我将这个数组打印到屏幕上，但是我不想在每次状态改变时都打印一个新的2d数组，而是想用新状态覆盖终端中的旧数组.

So, for example, I will have a 2d char array, where each element will contain either a '#' or a '-'. I will print this array onto the screen, but rather than printing a new 2d array every time there is a state change, I want to overwrite the old array in the terminal with the new state.

我一直在寻找实现此目标的方法，但是运气还不太好.我发现最接近的是printf函数(\ r)中的回车符，但是希望有人可以告诉我执行此操作的最佳方法.

I have looked for ways to do this, but haven't had much luck. The closest I have found is a carriage return in the printf function (\r), but hopefully someone can tell me the best way to do this.

具体地说，我如何在屏幕上打印2d数组，更改数组的元素，并在旧数组的顶部打印出新数组，即覆盖它.

Specifically, how could I print out a 2d array on the screen, change the elements of the array, and print out the new array ON TOP of the old one, ie, overwrite it.

推荐答案

(其中一些链接，代码片段是Linux，其他是Windows)
给出您的具体问题 ，(并假设您确实知道如何向控制台写入数组):

(some of these links, code snippets are Linux, and others are Windows)
Given your specific questions, (and assuming you do know how to write an array to the console) :

1) 写入第一个数组.
2) ，然后清除控制台(或覆盖控制台)
像这样:

1) write the first array.
2) Then Clear The Console (or over write the console)
Something like this:

#include <stdlib.h>

void main()
{
   system("cls");
}     

或将以下内容写入stdout:(Linux)

Or write the following to stdout: (Linux)

write(1,"\E[H\E[2J",7);

/usr/bin/clear会执行此操作，除了不会创建另一个进程.
或全部:

which is what /usr/bin/clear does except it does not create another process.
Or both:

 void clear_screen()
 {
  #ifdef WINDOWS
     system ( "CLS" );
  #else
     // Assume POSIX
     system ( "clear" );
  #endif
 }  

此处有更多选项

3) 写下一个数组

3) write the next array

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