检查Python列表中是否有东西 [英] Check if something is (not) in a list in Python
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问题描述
我在 Python 中有一个元组列表,并且我有条件仅在元组不在列表中的情况下我才想在哪里分支(如果在列表中,那么我就不想在if分支中)
I have a list of tuples in Python, and I have a conditional where I want to take the branch ONLY if the tuple is not in the list (if it is in the list, then I don't want to take the if branch)
if curr_x -1 > 0 and (curr_x-1 , curr_y) not in myList:
# Do Something
这对我来说并不是很有效.我做错了什么?
This is not really working for me though. What have I done wrong?
推荐答案
该错误可能在代码中的其他地方,因为它应该可以正常工作:
The bug is probably somewhere else in your code, because it should work fine:
>>> 3 not in [2, 3, 4]
False
>>> 3 not in [4, 5, 6]
True
或带有元组:
>>> (2, 3) not in [(2, 3), (5, 6), (9, 1)]
False
>>> (2, 3) not in [(2, 7), (7, 3), "hi"]
True
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