如何在python中构造一组列表项? [英] How to construct a set out of list items in python?

问题描述

我在python中有一个文件名list，我想从所有文件名中构造一个set.

I have a list of filenames in python and I would want to construct a set out of all the filenames.

filelist=[]
for filename in filelist:
    set(filename)

这似乎不起作用.该怎么办?

This does not seem to work. How can do this?

推荐答案

如果您具有可哈希对象的列表(文件名可能是字符串，因此应该算在内):

If you have a list of hashable objects (filenames would probably be strings, so they should count):

lst = ['foo.py', 'bar.py', 'baz.py', 'qux.py', Ellipsis]

您可以直接构造集合:

s = set(lst)

实际上，set可以与任何可迭代对象一起使用！(鸭子输入不是很好吗?)

In fact, set will work this way with any iterable object! (Isn't duck typing great?)

如果要反复进行:

s = set()
for item in iterable:
    s.add(item)

但是很少需要这样做.我之所以仅提及它，是因为set.add方法非常有用.

But there's rarely a need to do it this way. I only mention it because the set.add method is quite useful.

这篇关于如何在python中构造一组列表项?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！