如何将列表中的所有整数相乘 [英] How to multiply all integers inside list

问题描述

你好，所以我想将列表中的整数相乘.

Hello so I want to multiply the integers inside a list.

例如；

l = [1, 2, 3]
l = [1*2, 2*2, 3*2]

输出:

l = [2, 4, 6]

所以我在网上搜索，大多数答案是将所有整数彼此相乘，例如:

So I was searching online and most of the answers were regarding multiply all the integers with each other such as:

[1 * 2 * 3]

[1*2*3]

推荐答案

尝试这通过l进行，将每个元素乘以2.

This goes through l, multiplying each element by two.

当然，有多种方法可以做到这一点.如果您正在使用 lambda函数和

Of course, there's more than one way to do it. If you're into lambda functions and map, you can even do

l = map(lambda x: x * 2, l)

将功能lambda x: x * 2应用到l中的每个元素.这等效于:

to apply the function lambda x: x * 2 to each element in l. This is equivalent to:

def timesTwo(x):
    return x * 2

l = map(timesTwo, l)

请注意，map()返回一个地图对象，而不是列表，因此，如果以后确实需要列表，则可以在以后使用list()函数，例如:

Note that map() returns a map object, not a list, so if you really need a list afterwards you can use the list() function afterwards, for instance:

l = list(map(timesTwo, l))

感谢 Minyc510在注释中这种澄清.

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