Python如何获取二维列表中的每个第一个元素 [英] Python How to get every first element in 2 Dimensional List

问题描述

我有一个这样的列表:

a = ((4.0, 4, 4.0), (3.0, 3, 3.6), (3.5, 6, 4.8))

我想要这样的结果(每个列表中的第一个元素):

I want an outcome like this (EVERY first element in the list) :

4.0, 3.0, 3.5

我尝试了[[:: 1] [0]，但不起作用

I tried a[::1][0], but it doesn't work

我几周前才开始学习Python. Python版本= 2.7.9

I'm just start learning Python weeks ago. Python version = 2.7.9

推荐答案

您可以从列表理解的每个元素中获取索引[0]

You can get the index [0] from each element in a list comprehension

>>> [i[0] for i in a]
[4.0, 3.0, 3.5]

也只是想学什么，您没有list的list，却没有tuple的tuple.

Also just to be pedantic, you don't have a list of list, you have a tuple of tuple.

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